118 lines
4.9 KiB
Java
118 lines
4.9 KiB
Java
//给你一个数组 orders，表示客户在餐厅中完成的订单，确切地说， orders[i]=[customerNamei,tableNumberi,foodIt
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//emi] ，其中 customerNamei 是客户的姓名，tableNumberi 是客户所在餐桌的桌号，而 foodItemi 是客户点的餐品名称。
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//
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// 请你返回该餐厅的 点菜展示表 。在这张表中，表中第一行为标题，其第一列为餐桌桌号 “Table” ，后面每一列都是按字母顺序排列的餐品名称。接下来每一行中
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//的项则表示每张餐桌订购的相应餐品数量，第一列应当填对应的桌号，后面依次填写下单的餐品数量。
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//
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// 注意：客户姓名不是点菜展示表的一部分。此外，表中的数据行应该按餐桌桌号升序排列。
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//
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//
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//
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// 示例 1：
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//
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// 输入：orders = [["David","3","Ceviche"],["Corina","10","Beef Burrito"],["David",
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//"3","Fried Chicken"],["Carla","5","Water"],["Carla","5","Ceviche"],["Rous","3","
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//Ceviche"]]
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//输出：[["Table","Beef Burrito","Ceviche","Fried Chicken","Water"],["3","0","2","1
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//","0"],["5","0","1","0","1"],["10","1","0","0","0"]]
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//解释：
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//点菜展示表如下所示：
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//Table,Beef Burrito,Ceviche,Fried Chicken,Water
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//3 ,0 ,2 ,1 ,0
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//5 ,0 ,1 ,0 ,1
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//10 ,1 ,0 ,0 ,0
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//对于餐桌 3：David 点了 "Ceviche" 和 "Fried Chicken"，而 Rous 点了 "Ceviche"
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//而餐桌 5：Carla 点了 "Water" 和 "Ceviche"
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//餐桌 10：Corina 点了 "Beef Burrito"
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//
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//
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// 示例 2：
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//
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// 输入：orders = [["James","12","Fried Chicken"],["Ratesh","12","Fried Chicken"],[
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//"Amadeus","12","Fried Chicken"],["Adam","1","Canadian Waffles"],["Brianna","1","
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//Canadian Waffles"]]
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//输出：[["Table","Canadian Waffles","Fried Chicken"],["1","2","0"],["12","0","3"]]
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//
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//解释：
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//对于餐桌 1：Adam 和 Brianna 都点了 "Canadian Waffles"
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//而餐桌 12：James, Ratesh 和 Amadeus 都点了 "Fried Chicken"
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//
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//
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// 示例 3：
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//
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// 输入：orders = [["Laura","2","Bean Burrito"],["Jhon","2","Beef Burrito"],["Melis
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//sa","2","Soda"]]
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//输出：[["Table","Bean Burrito","Beef Burrito","Soda"],["2","1","1","1"]]
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//
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//
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//
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//
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// 提示：
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//
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//
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// 1 <= orders.length <= 5 * 10^4
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// orders[i].length == 3
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// 1 <= customerNamei.length, foodItemi.length <= 20
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// customerNamei 和 foodItemi 由大小写英文字母及空格字符 ' ' 组成。
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// tableNumberi 是 1 到 500 范围内的整数。
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//
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// Related Topics 数组 哈希表 字符串 有序集合 排序
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// 👍 30 👎 0
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package leetcode.editor.cn;
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import java.util.*;
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import java.util.stream.Collectors;
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//1418:点菜展示表
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public class DisplayTableOfFoodOrdersInARestaurant {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new DisplayTableOfFoodOrdersInARestaurant().new Solution();
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System.out.println(solution.displayTable(
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Arrays.asList(
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Arrays.asList("David", "3", "Ceviche"),
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Arrays.asList("Corina", "10", "Beef Burrito"),
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Arrays.asList("David", "3", "Fried Chicken"),
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Arrays.asList("Carla", "5", "Water"),
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Arrays.asList("Carla", "5", "Ceviche"),
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Arrays.asList("Rous", "3", "Ceviche")
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)
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// new ListListString("[[\"David\",\"3\",\"Ceviche\"],[\"Corina\",\"10\",\"Beef Burrito\"],[\"David\",\"3\",\"Fried Chicken\"],[\"Carla\",\"5\",\"Water\"],[\"Carla\",\"5\",\"Ceviche\"],[\"Rous\",\"3\",\"Ceviche\"]]").get()
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));
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public List<List<String>> displayTable(List<List<String>> orders) {
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Map<Integer, Map<String, Integer>> map = new HashMap<>();
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Set<String> foods = new HashSet<>();
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for (List<String> order : orders) {
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int key = Integer.parseInt(order.get(1));
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Map<String, Integer> orderMap = map.getOrDefault(key, new HashMap<>());
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orderMap.put(order.get(2), orderMap.getOrDefault(order.get(2), 0) + 1);
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map.put(key, orderMap);
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foods.add(order.get(2));
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}
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List<String> items = foods.stream().sorted().collect(Collectors.toList());
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items.add(0, "Table");
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orders = new ArrayList<>();
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orders.add(items);
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Object[] keys = map.keySet().toArray();
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Arrays.sort(keys);
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for (Object key : keys) {
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List<String> list = new ArrayList<>();
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for (int i = 1; i < items.size(); i++) {
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list.add(map.get(key).getOrDefault(items.get(i), 0).toString());
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}
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list.add(0, key.toString());
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orders.add(list);
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}
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return orders;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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} |