//给你一个数组 orders,表示客户在餐厅中完成的订单,确切地说, orders[i]=[customerNamei,tableNumberi,foodIt //emi] ,其中 customerNamei 是客户的姓名,tableNumberi 是客户所在餐桌的桌号,而 foodItemi 是客户点的餐品名称。 // // 请你返回该餐厅的 点菜展示表 。在这张表中,表中第一行为标题,其第一列为餐桌桌号 “Table” ,后面每一列都是按字母顺序排列的餐品名称。接下来每一行中 //的项则表示每张餐桌订购的相应餐品数量,第一列应当填对应的桌号,后面依次填写下单的餐品数量。 // // 注意:客户姓名不是点菜展示表的一部分。此外,表中的数据行应该按餐桌桌号升序排列。 // // // // 示例 1: // // 输入:orders = [["David","3","Ceviche"],["Corina","10","Beef Burrito"],["David", //"3","Fried Chicken"],["Carla","5","Water"],["Carla","5","Ceviche"],["Rous","3"," //Ceviche"]] //输出:[["Table","Beef Burrito","Ceviche","Fried Chicken","Water"],["3","0","2","1 //","0"],["5","0","1","0","1"],["10","1","0","0","0"]] //解释: //点菜展示表如下所示: //Table,Beef Burrito,Ceviche,Fried Chicken,Water //3 ,0 ,2 ,1 ,0 //5 ,0 ,1 ,0 ,1 //10 ,1 ,0 ,0 ,0 //对于餐桌 3:David 点了 "Ceviche" 和 "Fried Chicken",而 Rous 点了 "Ceviche" //而餐桌 5:Carla 点了 "Water" 和 "Ceviche" //餐桌 10:Corina 点了 "Beef Burrito" // // // 示例 2: // // 输入:orders = [["James","12","Fried Chicken"],["Ratesh","12","Fried Chicken"],[ //"Amadeus","12","Fried Chicken"],["Adam","1","Canadian Waffles"],["Brianna","1"," //Canadian Waffles"]] //输出:[["Table","Canadian Waffles","Fried Chicken"],["1","2","0"],["12","0","3"]] // //解释: //对于餐桌 1:Adam 和 Brianna 都点了 "Canadian Waffles" //而餐桌 12:James, Ratesh 和 Amadeus 都点了 "Fried Chicken" // // // 示例 3: // // 输入:orders = [["Laura","2","Bean Burrito"],["Jhon","2","Beef Burrito"],["Melis //sa","2","Soda"]] //输出:[["Table","Bean Burrito","Beef Burrito","Soda"],["2","1","1","1"]] // // // // // 提示: // // // 1 <= orders.length <= 5 * 10^4 // orders[i].length == 3 // 1 <= customerNamei.length, foodItemi.length <= 20 // customerNamei 和 foodItemi 由大小写英文字母及空格字符 ' ' 组成。 // tableNumberi 是 1 到 500 范围内的整数。 // // Related Topics 数组 哈希表 字符串 有序集合 排序 // 👍 30 👎 0 package leetcode.editor.cn; import java.util.*; import java.util.stream.Collectors; //1418:点菜展示表 public class DisplayTableOfFoodOrdersInARestaurant { public static void main(String[] args) { //测试代码 Solution solution = new DisplayTableOfFoodOrdersInARestaurant().new Solution(); System.out.println(solution.displayTable( Arrays.asList( Arrays.asList("David", "3", "Ceviche"), Arrays.asList("Corina", "10", "Beef Burrito"), Arrays.asList("David", "3", "Fried Chicken"), Arrays.asList("Carla", "5", "Water"), Arrays.asList("Carla", "5", "Ceviche"), Arrays.asList("Rous", "3", "Ceviche") ) // new ListListString("[[\"David\",\"3\",\"Ceviche\"],[\"Corina\",\"10\",\"Beef Burrito\"],[\"David\",\"3\",\"Fried Chicken\"],[\"Carla\",\"5\",\"Water\"],[\"Carla\",\"5\",\"Ceviche\"],[\"Rous\",\"3\",\"Ceviche\"]]").get() )); } //力扣代码 //leetcode submit region begin(Prohibit modification and deletion) class Solution { public List> displayTable(List> orders) { Map> map = new HashMap<>(); Set foods = new HashSet<>(); for (List order : orders) { int key = Integer.parseInt(order.get(1)); Map orderMap = map.getOrDefault(key, new HashMap<>()); orderMap.put(order.get(2), orderMap.getOrDefault(order.get(2), 0) + 1); map.put(key, orderMap); foods.add(order.get(2)); } List items = foods.stream().sorted().collect(Collectors.toList()); items.add(0, "Table"); orders = new ArrayList<>(); orders.add(items); Object[] keys = map.keySet().toArray(); Arrays.sort(keys); for (Object key : keys) { List list = new ArrayList<>(); for (int i = 1; i < items.size(); i++) { list.add(map.get(key).getOrDefault(items.get(i), 0).toString()); } list.add(0, key.toString()); orders.add(list); } return orders; } } //leetcode submit region end(Prohibit modification and deletion) }