100 lines
3.3 KiB
Java
100 lines
3.3 KiB
Java
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//给你一个整数数组 nums 和一个整数 k 。区间 [left, right]（left <= right）的 异或结果 是对下标位于 left 和 rig
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//ht（包括 left 和 right ）之间所有元素进行 XOR 运算的结果：nums[left] XOR nums[left+1] XOR ... XOR n
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//ums[right] 。
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//
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// 返回数组中 要更改的最小元素数 ，以使所有长度为 k 的区间异或结果等于零。
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//
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//
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//
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// 示例 1：
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//
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//
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//输入：nums = [1,2,0,3,0], k = 1
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//输出：3
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//解释：将数组 [1,2,0,3,0] 修改为 [0,0,0,0,0]
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//
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//
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// 示例 2：
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//
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//
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//输入：nums = [3,4,5,2,1,7,3,4,7], k = 3
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//输出：3
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//解释：将数组 [3,4,5,2,1,7,3,4,7] 修改为 [3,4,7,3,4,7,3,4,7]
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//
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//
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// 示例 3：
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//
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//
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//输入：nums = [1,2,4,1,2,5,1,2,6], k = 3
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//输出：3
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//解释：将数组[1,2,4,1,2,5,1,2,6] 修改为 [1,2,3,1,2,3,1,2,3]
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//
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//
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//
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// 提示：
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//
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//
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// 1 <= k <= nums.length <= 2000
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// 0 <= nums[i] < 210
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//
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// Related Topics 动态规划
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// 👍 57 👎 0
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package leetcode.editor.cn;
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import java.util.*;
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//1787:使所有区间的异或结果为零
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public class MakeTheXorOfAllSegmentsEqualToZero {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new MakeTheXorOfAllSegmentsEqualToZero().new Solution();
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//3
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System.out.println(solution.minChanges(new int[]{1,2,0,3,0},1));
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//3
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System.out.println(solution.minChanges(new int[]{3,4,5,2,1,7,3,4,7},3));
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//3
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System.out.println(solution.minChanges(new int[]{1, 2, 4, 1, 2, 5, 1, 2, 6}, 3));
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//11
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System.out.println(solution.minChanges(new int[]{26,19,19,28,13,14,6,25,28,19,0,15,25,11}, 3));
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//11
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System.out.println(solution.minChanges(new int[]{11,20,3,18,26,30,20,7,3,0,25,9,19,21,3,23}, 5));
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public int minChanges(int[] nums, int k) {
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List<Map<Integer, Integer>> list = new ArrayList<>();
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for (int i = 0; i < k; i++) {
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list.add(new HashMap<>());
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}
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for (int i = 0; i < nums.length; i++) {
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int index = i % k;
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Map<Integer, Integer> map = list.get(index);
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map.put(nums[i], map.getOrDefault(nums[i], 0) + 1);
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list.set(index, map);
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}
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int[] flag = new int[1 << 10];
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Arrays.fill(flag, Integer.MAX_VALUE / 2);
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flag[0] = 0;
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int length = nums.length % k == 0 ? nums.length / k : nums.length / k + 1;
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for (int i = 0; i < k; i++) {
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Map<Integer, Integer> map = list.get(i);
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int min = Arrays.stream(flag).min().getAsInt();
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int[] temp = new int[1 << 10];
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Arrays.fill(temp, min);
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for (int j = 0; j < (1 << 10); j++) {
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for (int key : map.keySet()) {
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temp[j] = Math.min(temp[j], flag[j ^ key] - map.get(key));
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}
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temp[j] += i < nums.length % k || nums.length % k == 0 ? length : length - 1;
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}
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flag = temp;
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}
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return flag[0];
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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