2021-08-03 17:11:10 +08:00
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//一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为 “Start” )。
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//
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// 机器人每次只能向下或者向右移动一步。机器人试图达到网格的右下角(在下图中标记为 “Finish” )。
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//
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// 问总共有多少条不同的路径?
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//
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//
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//
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// 示例 1:
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//
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//
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//输入:m = 3, n = 7
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//输出:28
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//
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// 示例 2:
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//
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//
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//输入:m = 3, n = 2
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//输出:3
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//解释:
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//从左上角开始,总共有 3 条路径可以到达右下角。
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//1. 向右 -> 向下 -> 向下
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//2. 向下 -> 向下 -> 向右
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//3. 向下 -> 向右 -> 向下
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//
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//
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// 示例 3:
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//
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//
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//输入:m = 7, n = 3
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//输出:28
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//
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//
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// 示例 4:
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//
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//
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//输入:m = 3, n = 3
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//输出:6
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//
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//
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//
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// 提示:
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//
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//
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// 1 <= m, n <= 100
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// 题目数据保证答案小于等于 2 * 109
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//
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// Related Topics 数学 动态规划 组合数学
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// 👍 1065 👎 0
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package leetcode.editor.cn;
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/**
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* @author huangge1199
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*/
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//62:不同路径
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public class UniquePaths {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new UniquePaths().new Solution();
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public int uniquePaths(int m, int n) {
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2021-08-09 23:26:21 +08:00
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int[][] f = new int[m][n];
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for (int i = 0; i < m; ++i) {
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f[i][0] = 1;
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}
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for (int j = 0; j < n; ++j) {
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f[0][j] = 1;
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}
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for (int i = 1; i < m; ++i) {
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for (int j = 1; j < n; ++j) {
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f[i][j] = f[i - 1][j] + f[i][j - 1];
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}
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}
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return f[m - 1][n - 1];
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2021-08-03 17:11:10 +08:00
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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