leet-code/src/main/java/leetcode/editor/cn/XuLieHuaErChaShuLcof.java

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//请实现两个函数,分别用来序列化和反序列化二叉树。
//
// 你需要设计一个算法来实现二叉树的序列化与反序列化。这里不限定你的序列 / 反序列化算法执行逻辑,你只需要保证一个二叉树可以被序列化为一个字符串并且将这个字
//符串反序列化为原始的树结构。
//
// 提示:输入输出格式与 LeetCode 目前使用的方式一致,详情请参阅 LeetCode 序列化二叉树的格式。你并非必须采取这种方式,你也可以采用其他的方
//法解决这个问题。
//
//
//
// 示例:
//
//
//输入root = [1,2,3,null,null,4,5]
//输出:[1,2,3,null,null,4,5]
//
//
//
//
// 注意:本题与主站 297 题相同https://leetcode-cn.com/problems/serialize-and-deserialize-b
//inary-tree/
// Related Topics 树 深度优先搜索 广度优先搜索 设计 字符串 二叉树
// 👍 175 👎 0
package leetcode.editor.cn;
import com.code.leet.entiy.TreeNode;
import java.util.LinkedList;
import java.util.Queue;
//剑指 Offer 37:序列化二叉树
public class XuLieHuaErChaShuLcof{
public static void main(String[] args) {
//测试代码
// Solution solution = new XuLieHuaErChaShuLcof().new Solution();
}
//力扣代码
//leetcode submit region begin(Prohibit modification and deletion)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Codec {
// Encodes a tree to a single string.
public String serialize(TreeNode root) {
String result = "";
if (root == null) {
return "null,";
}
result += root.val + ",";
result += serialize(root.left);
result += serialize(root.right);
return result;
}
// Decodes your encoded data to tree.
public TreeNode deserialize(String data) {
if ("null,".equals(data)) {
return null;
}
String[] strs = data.split(",");
Queue<String> queue = new LinkedList<>();
for (String str : strs) {
queue.offer(str);
}
return des(queue);
}
private TreeNode des(Queue<String> queue) {
String value = queue.poll();
if ("null".equals(value)) {
return null;
}
TreeNode root = new TreeNode(Integer.parseInt(value));
root.left = des(queue);
root.right = des(queue);
return root;
}
}
// Your Codec object will be instantiated and called as such:
// Codec codec = new Codec();
// codec.deserialize(codec.serialize(root));
//leetcode submit region end(Prohibit modification and deletion)
}