leet-code/src/main/java/leetcode/editor/cn/ImplementQueueUsingStacksLcci.java
2021-04-29 23:21:52 +08:00

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//实现一个MyQueue类该类用两个栈来实现一个队列。 示例: MyQueue queue = new MyQueue(); queue.push(1);
//queue.push(2); queue.peek(); // 返回 1 queue.pop(); // 返回 1 queue.empty(); // 返
//回 false 说明: 你只能使用标准的栈操作 -- 也就是只有 push to top, peek/pop from top, size 和 is empty
// 操作是合法的。 你所使用的语言也许不支持栈。你可以使用 list 或者 deque双端队列来模拟一个栈只要是标准的栈操作即可。 假设所有操作都是有效的
//(例如,一个空的队列不会调用 pop 或者 peek 操作)。 Related Topics 栈
// 👍 35 👎 0
package leetcode.editor.cn;
import java.util.Stack;
//面试题 03.04:化栈为队
public class ImplementQueueUsingStacksLcci {
public static void main(String[] args) {
//测试代码
// Solution solution = new ImplementQueueUsingStacksLcci().new Solution();
}
//力扣代码
//leetcode submit region begin(Prohibit modification and deletion)
class MyQueue {
Stack<Integer> stack1;
Stack<Integer> stack2;
/**
* Initialize your data structure here.
*/
public MyQueue() {
stack1 = new Stack<>();
stack2 = new Stack<>();
}
/**
* Push element x to the back of queue.
*/
public void push(int x) {
while (!stack1.empty()) {
stack2.push(stack1.pop());
}
stack1.push(x);
while (!stack2.isEmpty()) {
stack1.push(stack2.pop());
}
}
/**
* Removes the element from in front of queue and returns that element.
*/
public int pop() {
return stack1.pop();
}
/**
* Get the front element.
*/
public int peek() {
return stack1.peek();
}
/**
* Returns whether the queue is empty.
*/
public boolean empty() {
return stack1.empty();
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/
//leetcode submit region end(Prohibit modification and deletion)
}