leet-code/src/main/java/leetcode/editor/cn/SparseMatrixMultiplication.java

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//给你两个 稀疏矩阵 A 和 B请你返回 AB 的结果。你可以默认 A 的列数等于 B 的行数。
//
// 请仔细阅读下面的示例。
//
//
//
// 示例:
//
// 输入:
//
//A = [
// [ 1, 0, 0],
// [-1, 0, 3]
//]
//
//B = [
// [ 7, 0, 0 ],
// [ 0, 0, 0 ],
// [ 0, 0, 1 ]
//]
//
//输出:
//
// | 1 0 0 | | 7 0 0 | | 7 0 0 |
//AB = | -1 0 3 | x | 0 0 0 | = | -7 0 3 |
// | 0 0 1 |
//
// Related Topics 数组 哈希表 矩阵 👍 55 👎 0
package leetcode.editor.cn;
//311:稀疏矩阵的乘法
class SparseMatrixMultiplication {
public static void main(String[] args) {
//测试代码
Solution solution = new SparseMatrixMultiplication().new Solution();
}
//力扣代码
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public int[][] multiply(int[][] mat1, int[][] mat2) {
int[][] result = new int[mat1.length][mat2[0].length];
for (int i = 0; i < result.length; i++) {
for (int j = 0; j < result[0].length; j++) {
for (int k = 0; k < mat1[0].length; k++) {
result[i][j] += mat1[i][k] * mat2[k][j];
}
}
}
return result;
}
}
//leetcode submit region end(Prohibit modification and deletion)
}