//给你一个由 '1'(陆地)和 '0'(水)组成的的二维网格,请你计算网格中岛屿的数量。 // // 岛屿总是被水包围,并且每座岛屿只能由水平方向和/或竖直方向上相邻的陆地连接形成。 // // 此外,你可以假设该网格的四条边均被水包围。 // // // // 示例 1: // // //输入:grid = [ // ["1","1","1","1","0"], // ["1","1","0","1","0"], // ["1","1","0","0","0"], // ["0","0","0","0","0"] //] //输出:1 // // // 示例 2: // // //输入:grid = [ // ["1","1","0","0","0"], // ["1","1","0","0","0"], // ["0","0","1","0","0"], // ["0","0","0","1","1"] //] //输出:3 // // // // // 提示: // // // m == grid.length // n == grid[i].length // 1 <= m, n <= 300 // grid[i][j] 的值为 '0' 或 '1' // // Related Topics 深度优先搜索 广度优先搜索 并查集 数组 矩阵 // 👍 1212 👎 0 package leetcode.editor.cn; import java.util.Arrays; import java.util.LinkedList; import java.util.List; import java.util.Queue; //200:岛屿数量 public class NumberOfIslands { public static void main(String[] args) { //测试代码 Solution solution = new NumberOfIslands().new Solution(); System.out.println(solution.numIslands(new char[][]{ {'1', '1', '1', '1', '0'}, {'1', '1', '0', '1', '0'}, {'1', '1', '0', '0', '0'}, {'0', '0', '0', '0', '0'} })); } //力扣代码 //leetcode submit region begin(Prohibit modification and deletion) class Solution { public int numIslands(char[][] grid) { int count = 0; for(int i = 0; i < grid.length; i++) { for(int j = 0; j < grid[0].length; j++) { if(grid[i][j] == '1'){ dfs(grid, i, j); count++; } } } return count; } private void dfs(char[][] grid, int x, int y){ if(x < 0 || y < 0 || x >= grid.length || y >= grid[0].length || grid[x][y] == '0') { return; } grid[x][y] = '0'; dfs(grid, x + 1, y); dfs(grid, x, y + 1); dfs(grid, x - 1, y); dfs(grid, x, y - 1); } } //leetcode submit region end(Prohibit modification and deletion) }