//将非负整数 num 转换为其对应的英文表示。 // // // // 示例 1: // // //输入:num = 123 //输出:"One Hundred Twenty Three" // // // 示例 2: // // //输入:num = 12345 //输出:"Twelve Thousand Three Hundred Forty Five" // // // 示例 3: // // //输入:num = 1234567 //输出:"One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven" // // // 示例 4: // // //输入:num = 1234567891 //输出:"One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven //Thousand Eight Hundred Ninety One" // // // // // 提示: // // // 0 <= num <= 2³¹ - 1 // // Related Topics 递归 数学 字符串 👍 198 👎 0 package leetcode.editor.cn; //273:整数转换英文表示 class IntegerToEnglishWords { public static void main(String[] args) { //测试代码 Solution solution = new IntegerToEnglishWords().new Solution(); } //力扣代码 //leetcode submit region begin(Prohibit modification and deletion) class Solution { String[] singles = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"}; String[] teens = {"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"}; String[] tens = {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"}; String[] thousands = {"", "Thousand", "Million", "Billion"}; public String numberToWords(int num) { if (num == 0) { return "Zero"; } StringBuffer sb = new StringBuffer(); for (int i = 3, unit = 1000000000; i >= 0; i--, unit /= 1000) { int curNum = num / unit; if (curNum != 0) { num -= curNum * unit; StringBuffer curr = new StringBuffer(); recursion(curr, curNum); curr.append(thousands[i]).append(" "); sb.append(curr); } } return sb.toString().trim(); } public void recursion(StringBuffer curr, int num) { if (num == 0) { return; } else if (num < 10) { curr.append(singles[num]).append(" "); } else if (num < 20) { curr.append(teens[num - 10]).append(" "); } else if (num < 100) { curr.append(tens[num / 10]).append(" "); recursion(curr, num % 10); } else { curr.append(singles[num / 100]).append(" Hundred "); recursion(curr, num % 100); } } } //leetcode submit region end(Prohibit modification and deletion) }