1233:删除子文件夹
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//<p>你是一位系统管理员,手里有一份文件夹列表 <code>folder</code>,你的任务是要删除该列表中的所有 <strong>子文件夹</strong>,并以 <strong>任意顺序</strong> 返回剩下的文件夹。</p>
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//
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//<p>如果文件夹 <code>folder[i]</code> 位于另一个文件夹 <code>folder[j]</code> 下,那么 <code>folder[i]</code> 就是 <code>folder[j]</code> 的 <strong>子文件夹</strong> 。</p>
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//
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//<p>文件夹的「路径」是由一个或多个按以下格式串联形成的字符串:<font color="#c7254e"><font face="Menlo, Monaco, Consolas, Courier New, monospace"><span style="font-size:12.6px"><span style="background-color:#f9f2f4">'/'</span></span></font></font> 后跟一个或者多个小写英文字母。</p>
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//
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//<ul>
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// <li>例如,<code>"/leetcode"</code> 和 <code>"/leetcode/problems"</code> 都是有效的路径,而空字符串和 <code>"/"</code> 不是。</li>
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//</ul>
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//
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//<p> </p>
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//
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//<p><strong>示例 1:</strong></p>
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//
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//<pre>
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//<strong>输入:</strong>folder = ["/a","/a/b","/c/d","/c/d/e","/c/f"]
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//<strong>输出:</strong>["/a","/c/d","/c/f"]
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//<strong>解释:</strong>"/a/b" 是 "/a" 的子文件夹,而 "/c/d/e" 是 "/c/d" 的子文件夹。
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//</pre>
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//
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//<p><strong>示例 2:</strong></p>
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//
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//<pre>
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//<strong>输入:</strong>folder = ["/a","/a/b/c","/a/b/d"]
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//<strong>输出:</strong>["/a"]
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//<strong>解释:</strong>文件夹 "/a/b/c" 和 "/a/b/d" 都会被删除,因为它们都是 "/a" 的子文件夹。
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//</pre>
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//
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//<p><strong>示例 3:</strong></p>
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//
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//<pre>
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//<strong>输入:</strong> folder = ["/a/b/c","/a/b/ca","/a/b/d"]
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//<strong>输出:</strong> ["/a/b/c","/a/b/ca","/a/b/d"]</pre>
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//
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//<p> </p>
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//
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//<p><strong>提示:</strong></p>
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//
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//<ul>
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// <li><code>1 <= folder.length <= 4 * 10<sup>4</sup></code></li>
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// <li><code>2 <= folder[i].length <= 100</code></li>
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// <li><code>folder[i]</code> 只包含小写字母和 <code>'/'</code></li>
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// <li><code>folder[i]</code> 总是以字符 <code>'/'</code> 起始</li>
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// <li>每个文件夹名都是 <strong>唯一</strong> 的</li>
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//</ul>
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//
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//<div><div>Related Topics</div><div><li>字典树</li><li>数组</li><li>字符串</li></div></div><br><div><li>👍 112</li><li>👎 0</li></div>
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package leetcode.editor.cn;
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import java.util.ArrayList;
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import java.util.Arrays;
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import java.util.List;
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// 1233:删除子文件夹
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public class RemoveSubFoldersFromTheFilesystem {
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public static void main(String[] args) {
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Solution solution = new RemoveSubFoldersFromTheFilesystem().new Solution();
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// TO TEST
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}
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public List<String> removeSubfolders(String[] folder) {
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List<String> res = new ArrayList<>();
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Arrays.sort(folder);
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res.add(folder[0]);
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for (int i = 1; i < folder.length; i++) {
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if (!folder[i].startsWith(res.get(res.size() - 1) + "/")) {
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res.add(folder[i]);
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}
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}
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return res;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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@ -0,0 +1,47 @@
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<p>你是一位系统管理员,手里有一份文件夹列表 <code>folder</code>,你的任务是要删除该列表中的所有 <strong>子文件夹</strong>,并以 <strong>任意顺序</strong> 返回剩下的文件夹。</p>
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<p>如果文件夹 <code>folder[i]</code> 位于另一个文件夹 <code>folder[j]</code> 下,那么 <code>folder[i]</code> 就是 <code>folder[j]</code> 的 <strong>子文件夹</strong> 。</p>
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<p>文件夹的「路径」是由一个或多个按以下格式串联形成的字符串:<font color="#c7254e"><font face="Menlo, Monaco, Consolas, Courier New, monospace"><span style="font-size:12.6px"><span style="background-color:#f9f2f4">'/'</span></span></font></font> 后跟一个或者多个小写英文字母。</p>
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<ul>
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<li>例如,<code>"/leetcode"</code> 和 <code>"/leetcode/problems"</code> 都是有效的路径,而空字符串和 <code>"/"</code> 不是。</li>
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</ul>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<pre>
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<strong>输入:</strong>folder = ["/a","/a/b","/c/d","/c/d/e","/c/f"]
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<strong>输出:</strong>["/a","/c/d","/c/f"]
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<strong>解释:</strong>"/a/b" 是 "/a" 的子文件夹,而 "/c/d/e" 是 "/c/d" 的子文件夹。
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre>
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<strong>输入:</strong>folder = ["/a","/a/b/c","/a/b/d"]
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<strong>输出:</strong>["/a"]
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<strong>解释:</strong>文件夹 "/a/b/c" 和 "/a/b/d" 都会被删除,因为它们都是 "/a" 的子文件夹。
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</pre>
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<p><strong>示例 3:</strong></p>
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<pre>
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<strong>输入:</strong> folder = ["/a/b/c","/a/b/ca","/a/b/d"]
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<strong>输出:</strong> ["/a/b/c","/a/b/ca","/a/b/d"]</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>1 <= folder.length <= 4 * 10<sup>4</sup></code></li>
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<li><code>2 <= folder[i].length <= 100</code></li>
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<li><code>folder[i]</code> 只包含小写字母和 <code>'/'</code></li>
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<li><code>folder[i]</code> 总是以字符 <code>'/'</code> 起始</li>
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<li>每个文件夹名都是 <strong>唯一</strong> 的</li>
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</ul>
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<div><div>Related Topics</div><div><li>字典树</li><li>数组</li><li>字符串</li></div></div><br><div><li>👍 112</li><li>👎 0</li></div>
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