周赛276

2022-01-16 23:24:00 +08:00 · 2022-01-16 23:24:00 +08:00 · e3ade14e2b
commit e3ade14e2b
parent 7e97bc3a2e
2 changed files with 364 additions and 0 deletions
--- a/src/main/java/contest/y2022/m1/week/Solution276.java
+++ b/src/main/java/contest/y2022/m1/week/Solution276.java
@ -0,0 +1,81 @@
+package contest.y2022.m1.week;
+
+import com.code.leet.entiy.TwoArray;
+
+import java.util.*;
+
+/**
+ * @description:
+ * @author: Administrator
+ * @date: 2021/8/22-10:29
+ */
+public class Solution276 {
+    public static void main(String[] args) {
+        Solution276 solution = new Solution276();
+//        solution.divideString("abcdefghij", 3, 'x');
+        TwoArray twoArray = new TwoArray("[[3,2],[4,3],[4,4],[2,5]]", true);
+        System.out.println(solution.mostPoints(twoArray.getArr()));
+    }
+
+    public String[] divideString(String s, int k, char fill) {
+        char[] chs = s.toCharArray();
+        int length = s.length() % k == 0 ? s.length() / k : s.length() / k + 1;
+        String[] strs = new String[length];
+        Arrays.fill(strs, "");
+        int index = 0;
+        for (char ch : chs) {
+            if (strs[index].length() == k) {
+                index++;
+            }
+            strs[index] += ch;
+        }
+        for (int i = strs[index].length(); i < k; i++) {
+            strs[index] += fill;
+        }
+        return strs;
+    }
+
+    public int minMoves(int target, int maxDoubles) {
+        int count = 0;
+        while (target > 1) {
+            if (maxDoubles == 0) {
+                break;
+            }
+            if (target % 2 == 0) {
+                target /= 2;
+                maxDoubles--;
+            } else {
+                target--;
+            }
+            count++;
+        }
+        return target == 1 ? count : count + target - 1;
+    }
+
+    public long mostPoints(int[][] questions) {
+        Map<Integer, Integer> map = new HashMap<>();
+        long[][] nums = new long[questions.length][2];
+        long max = 0;
+        for (int i = 0; i < questions.length; i++) {
+            if (i > 0) {
+                nums[i][0] = Math.max(nums[i][0], nums[i - 1][0]);
+            }
+            nums[i][1] = nums[i][0] + questions[i][0];
+            if (i + questions[i][1] + 1 < questions.length) {
+                nums[i + questions[i][1] + 1][0] = Math.max(nums[i + questions[i][1] + 1][0], nums[i][1]);
+            }
+            max = Math.max(nums[i][1], max);
+        }
+        return max;
+    }
+
+    public long maxRunTime(int n, int[] batteries) {
+        long sum = 0;
+        long min = 0;
+        for (int battery : batteries) {
+            sum += battery;
+            min = Math.min(min, battery);
+        }
+        return batteries.length == n ? min : sum / n;
+    }
+}
--- a/src/main/java/leetcode/editor/cn/doc/solution/ji-suan-li-kou-yin-xing-de-qian-by-leetc-xogx.lcv
+++ b/src/main/java/leetcode/editor/cn/doc/solution/ji-suan-li-kou-yin-xing-de-qian-by-leetc-xogx.lcv
@ -0,0 +1,283 @@
+#### 方法一：暴力计算
+
+记当前的天数是第 $\textit{week}$ 周的第 $\textit{day}$ 天。我们从第一周的星期一开始存钱，记 $\textit{week} = 1$，$\textit{day} = 1$。一周内，每一天比前一天多存 $1$ 块钱。而每个周一，会比前一个周一多存 $1$ 块钱。因此，每天存的钱等于 $\textit{week} + \textit{day} - 1$。把每天存的钱相加就可以得到答案。
+
+* [sol1-Python3]
+
+```Python
+class Solution:
+    def totalMoney(self, n: int) -> int:
+        week, day = 1, 1
+        res = 0
+        for i in range(n):
+            res += week + day - 1
+            day += 1
+            if day == 8:
+                day = 1
+                week += 1
+        return res
+```
+
+* [sol1-Java]
+
+```Java
+class Solution {
+    public int totalMoney(int n) {
+        int week = 1, day = 1;
+        int res = 0;
+        for (int i = 0; i < n; ++i) {
+            res += week + day - 1;
+            ++day;
+            if (day == 8) {
+                day = 1;
+                ++week;
+            }
+        }
+        return res;
+    }
+}
+```
+
+* [sol1-C#]
+
+```C#
+public class Solution {
+    public int TotalMoney(int n) {
+        int week = 1, day = 1;
+        int res = 0;
+        for (int i = 0; i < n; ++i) {
+            res += week + day - 1;
+            ++day;
+            if (day == 8) {
+                day = 1;
+                ++week;
+            }
+        }
+        return res;
+    }
+}
+```
+
+* [sol1-C++]
+
+```C++
+class Solution {
+public:
+    int totalMoney(int n) {
+        int week = 1, day = 1;
+        int res = 0;
+        for (int i = 0; i < n; ++i) {
+            res += week + day - 1;
+            ++day;
+            if (day == 8) {
+                day = 1;
+                ++week;
+            }
+        }
+        return res;
+    }
+};
+```
+
+* [sol1-C]
+
+```C
+int totalMoney(int n){
+    int week = 1, day = 1;
+    int res = 0;
+    for (int i = 0; i < n; ++i) {
+        res += week + day - 1;
+        ++day;
+        if (day == 8) {
+            day = 1;
+            ++week;
+        }
+    }
+    return res;
+}
+```
+
+* [sol1-Golang]
+
+```go
+func totalMoney(n int) (ans int) {
+    week, day := 1, 1
+    for i := 0; i < n; i++ {
+        ans += week + day - 1
+        day++
+        if day == 8 {
+            day = 1
+            week++
+        }
+    }
+    return
+}
+```
+
+* [sol1-JavaScript]
+
+```JavaScript
+var totalMoney = function(n) {
+    let week = 1, day = 1;
+    let res = 0;
+    for (let i = 0; i < n; ++i) {
+        res += week + day - 1;
+        ++day;
+        if (day === 8) {
+            day = 1;
+            ++week;
+        }
+    }
+    return res;
+};
+```
+
+**复杂度分析**
+
+- 时间复杂度：$O(n)$。需要遍历一次 $n$ 得到答案。
+
+- 空间复杂度：$O(1)$。只需要用到常数空间。
+
+#### 方法二：等差数列求和进行优化
+
+因为每周七天存的钱之和比上一周多 $7$ 块，因此每周存的钱之和的序列是一个等差数列，我们可以用等差数列求和公式来求出所有完整的周存的钱总和。剩下的天数里，每天存的钱也是一个等差数列，可以用相同的公式进行求和。最后把两者相加可以得到答案。
+
+* [sol2-Python3]
+
+```Python
+class Solution:
+    def totalMoney(self, n: int) -> int:
+        # 所有完整的周存的钱
+        weekNumber = n // 7
+        firstWeekMoney = (1 + 7) * 7 // 2
+        lastWeekMoney = firstWeekMoney + 7 * (weekNumber - 1)
+        weekMoney = (firstWeekMoney + lastWeekMoney) * weekNumber // 2
+        # 剩下的不能构成一个完整的周的天数里存的钱
+        dayNumber = n % 7
+        firstDayMoney = 1 + weekNumber
+        lastDayMoney = firstDayMoney + dayNumber - 1
+        dayMoney = (firstDayMoney + lastDayMoney) * dayNumber // 2
+        return weekMoney + dayMoney
+```
+
+* [sol2-Java]
+
+```Java
+class Solution {
+    public int totalMoney(int n) {
+        // 所有完整的周存的钱
+        int weekNumber = n / 7;
+        int firstWeekMoney = (1 + 7) * 7 / 2;
+        int lastWeekMoney = firstWeekMoney + 7 * (weekNumber - 1);
+        int weekMoney = (firstWeekMoney + lastWeekMoney) * weekNumber / 2;
+        // 剩下的不能构成一个完整的周的天数里存的钱
+        int dayNumber = n % 7;
+        int firstDayMoney = 1 + weekNumber;
+        int lastDayMoney = firstDayMoney + dayNumber - 1;
+        int dayMoney = (firstDayMoney + lastDayMoney) * dayNumber / 2;
+        return weekMoney + dayMoney;
+    }
+}
+```
+
+* [sol2-C#]
+
+```C#
+public class Solution {
+    public int TotalMoney(int n) {
+        // 所有完整的周存的钱
+        int weekNumber = n / 7;
+        int firstWeekMoney = (1 + 7) * 7 / 2;
+        int lastWeekMoney = firstWeekMoney + 7 * (weekNumber - 1);
+        int weekMoney = (firstWeekMoney + lastWeekMoney) * weekNumber / 2;
+        // 剩下的不能构成一个完整的周的天数里存的钱
+        int dayNumber = n % 7;
+        int firstDayMoney = 1 + weekNumber;
+        int lastDayMoney = firstDayMoney + dayNumber - 1;
+        int dayMoney = (firstDayMoney + lastDayMoney) * dayNumber / 2;
+        return weekMoney + dayMoney;
+    }
+}
+```
+
+* [sol2-C++]
+
+```C++
+class Solution {
+public:
+    int totalMoney(int n) {
+        // 所有完整的周存的钱
+        int weekNumber = n / 7;
+        int firstWeekMoney = (1 + 7) * 7 / 2;
+        int lastWeekMoney = firstWeekMoney + 7 * (weekNumber - 1);
+        int weekMoney = (firstWeekMoney + lastWeekMoney) * weekNumber / 2;
+        // 剩下的不能构成一个完整的周的天数里存的钱
+        int dayNumber = n % 7;
+        int firstDayMoney = 1 + weekNumber;
+        int lastDayMoney = firstDayMoney + dayNumber - 1;
+        int dayMoney = (firstDayMoney + lastDayMoney) * dayNumber / 2;
+        return weekMoney + dayMoney;
+    }
+};
+```
+
+* [sol2-C]
+
+```C
+int totalMoney(int n){
+    // 所有完整的周存的钱
+    int weekNumber = n / 7;
+    int firstWeekMoney = (1 + 7) * 7 / 2;
+    int lastWeekMoney = firstWeekMoney + 7 * (weekNumber - 1);
+    int weekMoney = (firstWeekMoney + lastWeekMoney) * weekNumber / 2;
+    // 剩下的不能构成一个完整的周的天数里存的钱
+    int dayNumber = n % 7;
+    int firstDayMoney = 1 + weekNumber;
+    int lastDayMoney = firstDayMoney + dayNumber - 1;
+    int dayMoney = (firstDayMoney + lastDayMoney) * dayNumber / 2;
+    return weekMoney + dayMoney;
+}
+```
+
+* [sol2-Golang]
+
+```go
+func totalMoney(n int) (ans int) {
+    // 所有完整的周存的钱
+    weekNum := n / 7
+    firstWeekMoney := (1 + 7) * 7 / 2
+    lastWeekMoney := firstWeekMoney + 7*(weekNum-1)
+    weekMoney := (firstWeekMoney + lastWeekMoney) * weekNum / 2
+    // 剩下的不能构成一个完整的周的天数里存的钱
+    dayNum := n % 7
+    firstDayMoney := 1 + weekNum
+    lastDayMoney := firstDayMoney + dayNum - 1
+    dayMoney := (firstDayMoney + lastDayMoney) * dayNum / 2
+    return weekMoney + dayMoney
+}
+```
+
+* [sol2-JavaScript]
+
+```JavaScript
+var totalMoney = function(n) {
+    // 所有完整的周存的钱
+    const weekNumber = Math.floor(n / 7);
+    const firstWeekMoney = Math.floor((1 + 7) * 7 / 2);
+    const lastWeekMoney = firstWeekMoney + 7 * (weekNumber - 1);
+    const weekMoney = Math.floor((firstWeekMoney + lastWeekMoney) * weekNumber / 2);
+    // 剩下的不能构成一个完整的周的天数里存的钱
+    const dayNumber = n % 7;
+    const firstDayMoney = 1 + weekNumber;
+    const lastDayMoney = firstDayMoney + dayNumber - 1;
+    const dayMoney = Math.floor((firstDayMoney + lastDayMoney) * dayNumber / 2);
+    return weekMoney + dayMoney;
+};
+```
+
+**复杂度分析**
+
+- 时间复杂度：$O(1)$。只需要用到常数时间。
+
+- 空间复杂度：$O(1)$。只需要用到常数空间。
+