344:反转字符串
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src/main/java/leetcode/editor/cn/ReverseString.java
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src/main/java/leetcode/editor/cn/ReverseString.java
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//编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
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//
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// 不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
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//
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// 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
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//
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//
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//
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// 示例 1:
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//
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// 输入:["h","e","l","l","o"]
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//输出:["o","l","l","e","h"]
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//
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//
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// 示例 2:
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//
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// 输入:["H","a","n","n","a","h"]
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//输出:["h","a","n","n","a","H"]
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// Related Topics 递归 双指针 字符串
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// 👍 422 👎 0
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package leetcode.editor.cn;
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//344:反转字符串
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public class ReverseString {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new ReverseString().new Solution();
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public void reverseString(char[] s) {
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int length = s.length;
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int size = length % 2 == 0 ? length / 2 : length / 2 + 1;
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for (int i = 0; i < size; i++) {
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char temp = s[i];
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s[i] = s[length - 1 - i];
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s[length - 1 - i] = temp;
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}
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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19
src/main/java/leetcode/editor/cn/ReverseString.md
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src/main/java/leetcode/editor/cn/ReverseString.md
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<p>编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 <code>char[]</code> 的形式给出。</p>
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<p>不要给另外的数组分配额外的空间,你必须<strong><a href="https://baike.baidu.com/item/原地算法" target="_blank">原地</a>修改输入数组</strong>、使用 O(1) 的额外空间解决这一问题。</p>
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<p>你可以假设数组中的所有字符都是 <a href="https://baike.baidu.com/item/ASCII" target="_blank">ASCII</a> 码表中的可打印字符。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<pre><strong>输入:</strong>["h","e","l","l","o"]
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<strong>输出:</strong>["o","l","l","e","h"]
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre><strong>输入:</strong>["H","a","n","n","a","h"]
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<strong>输出:</strong>["h","a","n","n","a","H"]</pre>
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<div><div>Related Topics</div><div><li>递归</li><li>双指针</li><li>字符串</li></div></div>\n<div><li>👍 422</li><li>👎 0</li></div>
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// 👍 300 👎 0
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// 👍 300 👎 0
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package leetcode.editor.cn;
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package leetcode.editor.cn;
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//557:反转字符串中的单词 III
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//557:反转字符串中的单词 III
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public class ReverseWordsInAStringIii{
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public class ReverseWordsInAStringIii {
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public static void main(String[] args) {
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public static void main(String[] args) {
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//测试代码
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//测试代码
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Solution solution = new ReverseWordsInAStringIii().new Solution();
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Solution solution = new ReverseWordsInAStringIii().new Solution();
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}
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}
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//力扣代码
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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class Solution {
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public String reverseWords(String s) {
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public String reverseWords(String s) {
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StringBuilder str = new StringBuilder();
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StringBuilder str = new StringBuilder();
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StringBuilder ss = new StringBuilder();
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StringBuilder ss = new StringBuilder();
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for (char ch:s.toCharArray()){
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for (char ch : s.toCharArray()) {
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if(ch!=' '){
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if (ch != ' ') {
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str.append(ch);
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str.append(ch);
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}else{
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} else {
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ss.append(str.reverse()).append(" ");
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ss.append(str.reverse()).append(" ");
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str = new StringBuilder();
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str = new StringBuilder();
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}
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}
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}
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ss.append(str.reverse());
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return ss.toString();
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}
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}
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ss.append(str.reverse());
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return ss.toString();
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}
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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//leetcode submit region end(Prohibit modification and deletion)
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}
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}
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