力扣:445. 两数相加 II

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huangge1199 2021-02-19 11:45:42 +08:00
parent 33e2f1aa4c
commit dc808e4af5

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@ -0,0 +1,83 @@
package com.code.leet.study.t2021.t20210219;
import com.code.leet.entiy.ListNode;
import java.util.ArrayList;
import java.util.List;
/**
* 给你两个 非空 链表来代表两个非负整数数字最高位位于链表开始位置它们的每个节点只存储一位数字将这两数相加会返回一个新的链表
* <p>
* 你可以假设除了数字 0 之外这两个数字都不会以零开头
* <p>
* <p>
* <p>
* 进阶
* <p>
* 如果输入链表不能修改该如何处理换句话说你不能对列表中的节点进行翻转
* <p>
* <p>
* <p>
* 示例
* <p>
* 输入(7 -> 2 -> 4 -> 3) + (5 -> 6 -> 4)
* 输出7 -> 8 -> 0 -> 7
*/
public class AddTwoNumbers {
/**
* 445. 两数相加 II
*/
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
List<ListNode> list1 = new ArrayList<>();
List<ListNode> list2 = new ArrayList<>();
ListNode temp1 = l1;
ListNode temp2 = l2;
while (temp1 != null) {
list1.add(temp1);
temp1 = temp1.next;
}
while (temp2 != null) {
list2.add(temp2);
temp2 = temp2.next;
}
if (list1.size() > list2.size()) {
return add(list1,list2);
}else {
return add(list2,list1);
}
}
private ListNode add(List<ListNode> list1, List<ListNode> list2){
int sum = 0;
int size1 = list1.size();
int size2 = list2.size();
int i = 0;
for (; i < size2; i++) {
sum = list2.get(size2 - 1 - i).val + list1.get(size1 - 1 - i).val + sum;
list1.get(size1 - 1 - i).val = sum % 10;
sum = sum / 10;
}
while (sum > 0) {
if(size1 - 1 - i>=0){
sum = list1.get(size1 - 1 - i).val + sum;
list1.get(size1 - 1 - i).val = sum % 10;
sum = sum / 10;
i++;
}else{
break;
}
}
if(sum>0){
ListNode head = new ListNode(sum);
head.next = list1.get(0);
return head;
}
return list1.get(0);
}
}