From c3d57a5143b51145a3179dacdc8c432c34b4516b Mon Sep 17 00:00:00 2001 From: "huangge1199@hotmail.com" Date: Mon, 12 Jul 2021 23:40:49 +0800 Subject: [PATCH] =?UTF-8?q?695:=E5=B2=9B=E5=B1=BF=E7=9A=84=E6=9C=80?= =?UTF-8?q?=E5=A4=A7=E9=9D=A2=E7=A7=AF?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- .../leetcode/editor/cn/MaxAreaOfIsland.java | 75 +++++++++++++++++++ .../leetcode/editor/cn/MaxAreaOfIsland.md | 32 ++++++++ 2 files changed, 107 insertions(+) create mode 100644 src/main/java/leetcode/editor/cn/MaxAreaOfIsland.java create mode 100644 src/main/java/leetcode/editor/cn/MaxAreaOfIsland.md diff --git a/src/main/java/leetcode/editor/cn/MaxAreaOfIsland.java b/src/main/java/leetcode/editor/cn/MaxAreaOfIsland.java new file mode 100644 index 0000000..e0dc7d0 --- /dev/null +++ b/src/main/java/leetcode/editor/cn/MaxAreaOfIsland.java @@ -0,0 +1,75 @@ +//给定一个包含了一些 0 和 1 的非空二维数组 grid 。 +// +// 一个 岛屿 是由一些相邻的 1 (代表土地) 构成的组合,这里的「相邻」要求两个 1 必须在水平或者竖直方向上相邻。你可以假设 grid 的四个边缘都被 +//0(代表水)包围着。 +// +// 找到给定的二维数组中最大的岛屿面积。(如果没有岛屿,则返回面积为 0 。) +// +// +// +// 示例 1: +// +// [[0,0,1,0,0,0,0,1,0,0,0,0,0], +// [0,0,0,0,0,0,0,1,1,1,0,0,0], +// [0,1,1,0,1,0,0,0,0,0,0,0,0], +// [0,1,0,0,1,1,0,0,1,0,1,0,0], +// [0,1,0,0,1,1,0,0,1,1,1,0,0], +// [0,0,0,0,0,0,0,0,0,0,1,0,0], +// [0,0,0,0,0,0,0,1,1,1,0,0,0], +// [0,0,0,0,0,0,0,1,1,0,0,0,0]] +// +// +// 对于上面这个给定矩阵应返回 6。注意答案不应该是 11 ,因为岛屿只能包含水平或垂直的四个方向的 1 。 +// +// 示例 2: +// +// [[0,0,0,0,0,0,0,0]] +// +// 对于上面这个给定的矩阵, 返回 0。 +// +// +// +// 注意: 给定的矩阵grid 的长度和宽度都不超过 50。 +// Related Topics 深度优先搜索 广度优先搜索 并查集 数组 矩阵 +// 👍 505 👎 0 + +package leetcode.editor.cn; + +//695:岛屿的最大面积 +class MaxAreaOfIsland { + public static void main(String[] args) { + //测试代码 + Solution solution = new MaxAreaOfIsland().new Solution(); + } + + //力扣代码 + //leetcode submit region begin(Prohibit modification and deletion) + class Solution { + public int maxAreaOfIsland(int[][] grid) { + int max = 0; + for (int i = 0; i < grid.length; i++) { + for (int j = 0; j < grid[0].length; j++) { + if (grid[i][j] == 1) { + max = Math.max(max, dfs(grid, i, j)); + } + } + } + return max; + } + + private int dfs(int[][] grid, int x, int y) { + if (x < 0 || x >= grid.length || y < 0 || y >= grid[0].length || grid[x][y] == 0) { + return 0; + } + grid[x][y]=0; + int count = 1; + count += dfs(grid, x - 1, y); + count += dfs(grid, x + 1, y); + count += dfs(grid, x, y - 1); + count += dfs(grid, x, y + 1); + return count; + } + } +//leetcode submit region end(Prohibit modification and deletion) + +} \ No newline at end of file diff --git a/src/main/java/leetcode/editor/cn/MaxAreaOfIsland.md b/src/main/java/leetcode/editor/cn/MaxAreaOfIsland.md new file mode 100644 index 0000000..e361780 --- /dev/null +++ b/src/main/java/leetcode/editor/cn/MaxAreaOfIsland.md @@ -0,0 +1,32 @@ +

给定一个包含了一些 01 的非空二维数组 grid

+ +

一个 岛屿 是由一些相邻的 1 (代表土地) 构成的组合,这里的「相邻」要求两个 1 必须在水平或者竖直方向上相邻。你可以假设 grid 的四个边缘都被 0(代表水)包围着。

+ +

找到给定的二维数组中最大的岛屿面积。(如果没有岛屿,则返回面积为 0 。)

+ +

 

+ +

示例 1:

+ +
[[0,0,1,0,0,0,0,1,0,0,0,0,0],
+ [0,0,0,0,0,0,0,1,1,1,0,0,0],
+ [0,1,1,0,1,0,0,0,0,0,0,0,0],
+ [0,1,0,0,1,1,0,0,1,0,1,0,0],
+ [0,1,0,0,1,1,0,0,1,1,1,0,0],
+ [0,0,0,0,0,0,0,0,0,0,1,0,0],
+ [0,0,0,0,0,0,0,1,1,1,0,0,0],
+ [0,0,0,0,0,0,0,1,1,0,0,0,0]]
+
+ +

对于上面这个给定矩阵应返回 6。注意答案不应该是 11 ,因为岛屿只能包含水平或垂直的四个方向的 1

+ +

示例 2:

+ +
[[0,0,0,0,0,0,0,0]]
+ +

对于上面这个给定的矩阵, 返回 0

+ +

 

+ +

注意: 给定的矩阵grid 的长度和宽度都不超过 50。

+
Related Topics
  • 深度优先搜索
  • 广度优先搜索
  • 并查集
  • 数组
  • 矩阵
  • \n
  • 👍 505
  • 👎 0
  • \ No newline at end of file