525:连续数组
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src/main/java/leetcode/editor/cn/ContiguousArray.java
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src/main/java/leetcode/editor/cn/ContiguousArray.java
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//给定一个二进制数组 nums , 找到含有相同数量的 0 和 1 的最长连续子数组,并返回该子数组的长度。
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//
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//
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//
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// 示例 1:
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//
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//
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//输入: nums = [0,1]
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//输出: 2
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//说明: [0, 1] 是具有相同数量0和1的最长连续子数组。
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//
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// 示例 2:
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//
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//
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//输入: nums = [0,1,0]
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//输出: 2
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//说明: [0, 1] (或 [1, 0]) 是具有相同数量0和1的最长连续子数组。
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//
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//
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//
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// 提示:
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//
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//
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// 1 <= nums.length <= 105
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// nums[i] 不是 0 就是 1
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//
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// Related Topics 哈希表
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// 👍 300 👎 0
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package leetcode.editor.cn;
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import java.util.HashMap;
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import java.util.Map;
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//525:连续数组
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public class ContiguousArray {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new ContiguousArray().new Solution();
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public int findMaxLength(int[] nums) {
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int max = 0;
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Map<Integer, Integer> map = new HashMap<Integer, Integer>();
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int count = 0;
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map.put(count, -1);
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for (int i = 0; i < nums.length; i++) {
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if (nums[i] == 1) {
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count++;
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} else {
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count--;
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}
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if (map.containsKey(count)) {
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max = Math.max(max, i - map.get(count));
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} else {
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map.put(count, i);
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}
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}
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return max;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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src/main/java/leetcode/editor/cn/ContiguousArray.md
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src/main/java/leetcode/editor/cn/ContiguousArray.md
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<p>给定一个二进制数组 <code>nums</code> , 找到含有相同数量的 <code>0</code> 和 <code>1</code> 的最长连续子数组,并返回该子数组的长度。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<pre>
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<strong>输入:</strong> nums = [0,1]
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<strong>输出:</strong> 2
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<strong>说明:</strong> [0, 1] 是具有相同数量0和1的最长连续子数组。</pre>
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<p><strong>示例 2:</strong></p>
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<pre>
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<strong>输入:</strong> nums = [0,1,0]
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<strong>输出:</strong> 2
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<strong>说明:</strong> [0, 1] (或 [1, 0]) 是具有相同数量0和1的最长连续子数组。</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
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<li><code>nums[i]</code> 不是 <code>0</code> 就是 <code>1</code></li>
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</ul>
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<div><div>Related Topics</div><div><li>哈希表</li></div></div>\n<div><li>👍 300</li><li>👎 0</li></div>
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