diff --git a/src/main/java/leetcode/editor/cn/BasicCalculator.java b/src/main/java/leetcode/editor/cn/BasicCalculator.java
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+//给你一个字符串表达式 s ，请你实现一个基本计算器来计算并返回它的值。 
+//
+// 
+//
+// 示例 1： 
+//
+// 
+//输入：s = "1 + 1"
+//输出：2
+// 
+//
+// 示例 2： 
+//
+// 
+//输入：s = " 2-1 + 2 "
+//输出：3
+// 
+//
+// 示例 3： 
+//
+// 
+//输入：s = "(1+(4+5+2)-3)+(6+8)"
+//输出：23
+// 
+//
+// 
+//
+// 提示： 
+//
+// 
+// 1 <= s.length <= 3 * 105 
+// s 由数字、'+'、'-'、'('、')'、和 ' ' 组成 
+// s 表示一个有效的表达式 
+// 
+// Related Topics 栈 数学 
+// 👍 571 👎 0
+
+package leetcode.editor.cn;
+
+import java.util.*;
+
+//224:基本计算器
+public class BasicCalculator {
+    public static void main(String[] args) {
+        //测试代码
+        Solution solution = new BasicCalculator().new Solution();
+    }
+
+    //力扣代码
+    //leetcode submit region begin(Prohibit modification and deletion)
+    class Solution {
+        public int calculate(String s) {
+            Deque<Integer> ops = new LinkedList<Integer>();
+            ops.push(1);
+            int sign = 1;
+
+            int ret = 0;
+            int n = s.length();
+            int i = 0;
+            while (i < n) {
+                if (s.charAt(i) == ' ') {
+                    i++;
+                } else if (s.charAt(i) == '+') {
+                    sign = ops.peek();
+                    i++;
+                } else if (s.charAt(i) == '-') {
+                    sign = -ops.peek();
+                    i++;
+                } else if (s.charAt(i) == '(') {
+                    ops.push(sign);
+                    i++;
+                } else if (s.charAt(i) == ')') {
+                    ops.pop();
+                    i++;
+                } else {
+                    long num = 0;
+                    while (i < n && Character.isDigit(s.charAt(i))) {
+                        num = num * 10 + s.charAt(i) - '0';
+                        i++;
+                    }
+                    ret += sign * num;
+                }
+            }
+            return ret;
+        }
+    }
+//leetcode submit region end(Prohibit modification and deletion)
+
+}
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diff --git a/src/main/java/leetcode/editor/cn/BasicCalculator.md b/src/main/java/leetcode/editor/cn/BasicCalculator.md
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+<p>给你一个字符串表达式 <code>s</code> ，请你实现一个基本计算器来计算并返回它的值。</p>
+
+<p> </p>
+
+<p><strong>示例 1：</strong></p>
+
+<pre>
+<strong>输入：</strong>s = "1 + 1"
+<strong>输出：</strong>2
+</pre>
+
+<p><strong>示例 2：</strong></p>
+
+<pre>
+<strong>输入：</strong>s = " 2-1 + 2 "
+<strong>输出：</strong>3
+</pre>
+
+<p><strong>示例 3：</strong></p>
+
+<pre>
+<strong>输入：</strong>s = "(1+(4+5+2)-3)+(6+8)"
+<strong>输出：</strong>23
+</pre>
+
+<p> </p>
+
+<p><strong>提示：</strong></p>
+
+<ul>
+	<li><code>1 <= s.length <= 3 * 10<sup>5</sup></code></li>
+	<li><code>s</code> 由数字、<code>'+'</code>、<code>'-'</code>、<code>'('</code>、<code>')'</code>、和 <code>' '</code> 组成</li>
+	<li><code>s</code> 表示一个有效的表达式</li>
+</ul>
+<div><div>Related Topics</div><div><li>栈</li><li>数学</li></div></div>\n<div><li>👍 571</li><li>👎 0</li></div>
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