diff --git a/src/main/java/leetcode/editor/cn/BasicCalculatorIi.java b/src/main/java/leetcode/editor/cn/BasicCalculatorIi.java
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+//给你一个字符串表达式 s ，请你实现一个基本计算器来计算并返回它的值。 
+//
+// 整数除法仅保留整数部分。 
+//
+// 
+// 
+// 
+//
+// 示例 1： 
+//
+// 
+//输入：s = "3+2*2"
+//输出：7
+// 
+//
+// 示例 2： 
+//
+// 
+//输入：s = " 3/2 "
+//输出：1
+// 
+//
+// 示例 3： 
+//
+// 
+//输入：s = " 3+5 / 2 "
+//输出：5
+// 
+//
+// 
+//
+// 提示： 
+//
+// 
+// 1 <= s.length <= 3 * 105 
+// s 由整数和算符 ('+', '-', '*', '/') 组成，中间由一些空格隔开 
+// s 表示一个 有效表达式 
+// 表达式中的所有整数都是非负整数，且在范围 [0, 231 - 1] 内 
+// 题目数据保证答案是一个 32-bit 整数 
+// 
+// 
+// 
+// Related Topics 栈 字符串 
+// 👍 400 👎 0
+
+package leetcode.editor.cn;
+
+import java.util.Stack;
+
+//227:基本计算器 II
+public class BasicCalculatorIi {
+    public static void main(String[] args) {
+        //测试代码
+        Solution solution = new BasicCalculatorIi().new Solution();
+//        System.out.println(solution.calculate("3+2*2"));
+        System.out.println(solution.calculate(" 3/2 "));
+    }
+
+    //力扣代码
+    //leetcode submit region begin(Prohibit modification and deletion)
+    class Solution {
+        public int calculate(String s) {
+            int num = 0;
+            Stack<Integer> stack = new Stack<>();
+            char op = '+';
+            s=s.replace(" ","");
+            for (int i = 0; i < s.length(); i++) {
+                char ch = s.charAt(i);
+                if (Character.isDigit(ch)) {
+                    num = num * 10 + (ch - '0');
+                }
+                if (!Character.isDigit(ch) || i == s.length() - 1) {
+                    switch (op) {
+                        case '+':
+                            stack.push(num);
+                            break;
+                        case '-':
+                            stack.push(-num);
+                            break;
+                        case '*':
+                            stack.push(stack.pop() * num);
+                            break;
+                        default:
+                            stack.push(stack.pop() / num);
+                            break;
+                    }
+                    op = ch;
+                    num = 0;
+                }
+            }
+            int result = 0;
+            while (!stack.isEmpty()) {
+                result += stack.pop();
+            }
+            return result;
+        }
+    }
+//leetcode submit region end(Prohibit modification and deletion)
+
+}
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diff --git a/src/main/java/leetcode/editor/cn/BasicCalculatorIi.md b/src/main/java/leetcode/editor/cn/BasicCalculatorIi.md
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+<p>给你一个字符串表达式 <code>s</code> ，请你实现一个基本计算器来计算并返回它的值。</p>
+
+<p>整数除法仅保留整数部分。</p>
+
+<div class="original__bRMd">
+<div>
+<p> </p>
+
+<p><strong>示例 1：</strong></p>
+
+<pre>
+<strong>输入：</strong>s = "3+2*2"
+<strong>输出：</strong>7
+</pre>
+
+<p><strong>示例 2：</strong></p>
+
+<pre>
+<strong>输入：</strong>s = " 3/2 "
+<strong>输出：</strong>1
+</pre>
+
+<p><strong>示例 3：</strong></p>
+
+<pre>
+<strong>输入：</strong>s = " 3+5 / 2 "
+<strong>输出：</strong>5
+</pre>
+
+<p> </p>
+
+<p><strong>提示：</strong></p>
+
+<ul>
+	<li><code>1 <= s.length <= 3 * 10<sup>5</sup></code></li>
+	<li><code>s</code> 由整数和算符 <code>('+', '-', '*', '/')</code> 组成，中间由一些空格隔开</li>
+	<li><code>s</code> 表示一个 <strong>有效表达式</strong></li>
+	<li>表达式中的所有整数都是非负整数，且在范围 <code>[0, 2<sup>31</sup> - 1]</code> 内</li>
+	<li>题目数据保证答案是一个 <strong>32-bit 整数</strong></li>
+</ul>
+</div>
+</div>
+<div><div>Related Topics</div><div><li>栈</li><li>字符串</li></div></div>\n<div><li>👍 400</li><li>👎 0</li></div>
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