298:二叉树最长连续序列
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//<p>给你一棵指定的二叉树的根节点 <code>root</code> ,请你计算其中 <strong>最长连续序列路径</strong> 的长度。</p>
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//
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//<p><strong>最长连续序列路径</strong> 是依次递增 1 的路径。该路径,可以是从某个初始节点到树中任意节点,通过「父 - 子」关系连接而产生的任意路径。且必须从父节点到子节点,反过来是不可以的。</p>
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//
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//
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//<p><strong>示例 1:</strong></p>
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//<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-1-tree.jpg" style="width: 322px; height: 421px;" />
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//<pre>
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//<strong>输入:</strong>root = [1,null,3,2,4,null,null,null,5]
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//<strong>输出:</strong>3
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//<strong>解释:</strong>当中,最长连续序列是 <code>3-4-5 ,所以</code>返回结果为 <code>3 。</code>
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//</pre>
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//
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//<p><strong>示例 2:</strong></p>
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//<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-2-tree.jpg" style="width: 262px; height: 421px;" />
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//<pre>
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//<strong>输入:</strong>root = [2,null,3,2,null,1]
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//<strong>输出:</strong>2
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//<strong>解释:</strong>当中,最长连续序列是 <code>2-3 。注意,不是</code> <code>3-2-1,所以</code>返回 <code>2 。</code>
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//</pre>
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//
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//<p> </p>
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//
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//<p><strong>提示:</strong></p>
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//
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//<ul>
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// <li>树中节点的数目在范围 <code>[1, 3 * 10<sup>4</sup>]</code> 内</li>
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// <li><code>-3 * 10<sup>4</sup> <= Node.val <= 3 * 10<sup>4</sup></code></li>
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//</ul>
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//<div><div>Related Topics</div><div><li>树</li><li>深度优先搜索</li><li>二叉树</li></div></div><br><div><li>👍 89</li><li>👎 0</li></div>
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package leetcode.editor.cn;
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import com.code.leet.entiy.TreeNode;
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// 298:二叉树最长连续序列
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public class BinaryTreeLongestConsecutiveSequence {
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public static void main(String[] args) {
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Solution solution = new BinaryTreeLongestConsecutiveSequence().new Solution();
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// TO TEST
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}
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//leetcode submit region begin(Prohibit modification and deletion)
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/**
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* Definition for a binary tree node.
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* public class TreeNode {
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* int val;
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* TreeNode left;
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* TreeNode right;
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* TreeNode() {}
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* TreeNode(int val) { this.val = val; }
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* TreeNode(int val, TreeNode left, TreeNode right) {
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* this.val = val;
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* this.left = left;
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* this.right = right;
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* }
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* }
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*/
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class Solution {
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public int longestConsecutive(TreeNode root) {
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if (root == null) {
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return 0;
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}
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dfs(root, 300000, 1);
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return max;
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}
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int max = 0;
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private void dfs(TreeNode node, int parent, int count) {
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if (node == null) {
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max = Math.max(max, count);
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return;
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}
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if (node.val - parent == 1) {
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dfs(node.left, node.val, count + 1);
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dfs(node.right, node.val, count + 1);
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} else {
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max = Math.max(max, count);
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dfs(node.left, node.val, 1);
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dfs(node.right, node.val, 1);
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}
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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@ -0,0 +1,30 @@
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<p>给你一棵指定的二叉树的根节点 <code>root</code> ,请你计算其中 <strong>最长连续序列路径</strong> 的长度。</p>
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<p><strong>最长连续序列路径</strong> 是依次递增 1 的路径。该路径,可以是从某个初始节点到树中任意节点,通过「父 - 子」关系连接而产生的任意路径。且必须从父节点到子节点,反过来是不可以的。</p>
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<p><strong>示例 1:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-1-tree.jpg" style="width: 322px; height: 421px;" />
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<pre>
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<strong>输入:</strong>root = [1,null,3,2,4,null,null,null,5]
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<strong>输出:</strong>3
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<strong>解释:</strong>当中,最长连续序列是 <code>3-4-5 ,所以</code>返回结果为 <code>3 。</code>
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</pre>
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<p><strong>示例 2:</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-2-tree.jpg" style="width: 262px; height: 421px;" />
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<pre>
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<strong>输入:</strong>root = [2,null,3,2,null,1]
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<strong>输出:</strong>2
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<strong>解释:</strong>当中,最长连续序列是 <code>2-3 。注意,不是</code> <code>3-2-1,所以</code>返回 <code>2 。</code>
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li>树中节点的数目在范围 <code>[1, 3 * 10<sup>4</sup>]</code> 内</li>
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<li><code>-3 * 10<sup>4</sup> <= Node.val <= 3 * 10<sup>4</sup></code></li>
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</ul>
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<div><div>Related Topics</div><div><li>树</li><li>深度优先搜索</li><li>二叉树</li></div></div><br><div><li>👍 89</li><li>👎 0</li></div>
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