298:二叉树最长连续序列

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轩辕龙儿 2022-05-30 14:23:03 +08:00
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//<p>给你一棵指定的二叉树的根节点 <code>root</code> 请你计算其中 <strong>最长连续序列路径</strong> 的长度</p>
//
//<p><strong>最长连续序列路径</strong> 是依次递增 1 的路径该路径可以是从某个初始节点到树中任意节点通过 - 关系连接而产生的任意路径且必须从父节点到子节点反过来是不可以的</p>
//&nbsp;
//
//<p><strong>示例 1</strong></p>
//<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-1-tree.jpg" style="width: 322px; height: 421px;" />
//<pre>
//<strong>输入</strong>root = [1,null,3,2,4,null,null,null,5]
//<strong>输出</strong>3
//<strong>解释</strong>当中最长连续序列是 <code>3-4-5 所以</code>返回结果为 <code>3 </code>
//</pre>
//
//<p><strong>示例 2</strong></p>
//<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-2-tree.jpg" style="width: 262px; height: 421px;" />
//<pre>
//<strong>输入</strong>root = [2,null,3,2,null,1]
//<strong>输出</strong>2
//<strong>解释</strong>当中最长连续序列是 <code>2-3 注意不是</code> <code>3-2-1所以</code>返回 <code>2 </code>
//</pre>
//
//<p>&nbsp;</p>
//
//<p><strong>提示</strong></p>
//
//<ul>
// <li>树中节点的数目在范围 <code>[1, 3 * 10<sup>4</sup>]</code> </li>
// <li><code>-3 * 10<sup>4</sup> &lt;= Node.val &lt;= 3 * 10<sup>4</sup></code></li>
//</ul>
//<div><div>Related Topics</div><div><li></li><li>深度优先搜索</li><li>二叉树</li></div></div><br><div><li>👍 89</li><li>👎 0</li></div>
package leetcode.editor.cn;
import com.code.leet.entiy.TreeNode;
// 298:二叉树最长连续序列
public class BinaryTreeLongestConsecutiveSequence {
public static void main(String[] args) {
Solution solution = new BinaryTreeLongestConsecutiveSequence().new Solution();
// TO TEST
}
//leetcode submit region begin(Prohibit modification and deletion)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int longestConsecutive(TreeNode root) {
if (root == null) {
return 0;
}
dfs(root, 300000, 1);
return max;
}
int max = 0;
private void dfs(TreeNode node, int parent, int count) {
if (node == null) {
max = Math.max(max, count);
return;
}
if (node.val - parent == 1) {
dfs(node.left, node.val, count + 1);
dfs(node.right, node.val, count + 1);
} else {
max = Math.max(max, count);
dfs(node.left, node.val, 1);
dfs(node.right, node.val, 1);
}
}
}
//leetcode submit region end(Prohibit modification and deletion)
}

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<p>给你一棵指定的二叉树的根节点 <code>root</code> ,请你计算其中 <strong>最长连续序列路径</strong> 的长度。</p>
<p><strong>最长连续序列路径</strong> 是依次递增 1 的路径。该路径,可以是从某个初始节点到树中任意节点,通过「父 - 子」关系连接而产生的任意路径。且必须从父节点到子节点,反过来是不可以的。</p>
&nbsp;
<p><strong>示例 1</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-1-tree.jpg" style="width: 322px; height: 421px;" />
<pre>
<strong>输入:</strong>root = [1,null,3,2,4,null,null,null,5]
<strong>输出:</strong>3
<strong>解释:</strong>当中,最长连续序列是 <code>3-4-5 ,所以</code>返回结果为 <code>3 。</code>
</pre>
<p><strong>示例 2</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/03/14/consec1-2-tree.jpg" style="width: 262px; height: 421px;" />
<pre>
<strong>输入:</strong>root = [2,null,3,2,null,1]
<strong>输出:</strong>2
<strong>解释:</strong>当中,最长连续序列是 <code>2-3 。注意,不是</code> <code>3-2-1所以</code>返回 <code>2 。</code>
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li>树中节点的数目在范围 <code>[1, 3 * 10<sup>4</sup>]</code></li>
<li><code>-3 * 10<sup>4</sup> &lt;= Node.val &lt;= 3 * 10<sup>4</sup></code></li>
</ul>
<div><div>Related Topics</div><div><li></li><li>深度优先搜索</li><li>二叉树</li></div></div><br><div><li>👍 89</li><li>👎 0</li></div>