diff --git a/src/main/java/leetcode/editor/cn/FourSum.java b/src/main/java/leetcode/editor/cn/FourSum.java new file mode 100644 index 0000000..22a7bef --- /dev/null +++ b/src/main/java/leetcode/editor/cn/FourSum.java @@ -0,0 +1,116 @@ +//给你一个由 n 个整数组成的数组 nums ,和一个目标值 target 。请你找出并返回满足下述全部条件且不重复的四元组 [nums[a], nums[ +//b], nums[c], nums[d]] : +// +// +// 0 <= a, b, c, d < n +// a、b、c 和 d 互不相同 +// nums[a] + nums[b] + nums[c] + nums[d] == target +// +// +// 你可以按 任意顺序 返回答案 。 +// +// +// +// 示例 1: +// +// +//输入:nums = [1,0,-1,0,-2,2], target = 0 +//输出:[[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]] +// +// +// 示例 2: +// +// +//输入:nums = [2,2,2,2,2], target = 8 +//输出:[[2,2,2,2]] +// +// +// +// +// 提示: +// +// +// 1 <= nums.length <= 200 +// -10⁹ <= nums[i] <= 10⁹ +// -10⁹ <= target <= 10⁹ +// +// Related Topics 数组 双指针 排序 👍 976 👎 0 + +package leetcode.editor.cn; + +import java.util.ArrayList; +import java.util.Arrays; +import java.util.List; + +//18:四数之和 +class FourSum { + public static void main(String[] args) { + //测试代码 + Solution solution = new FourSum().new Solution(); +// solution.fourSum(new int[]{1,0,-1,0,-2,2},0); + solution.fourSum(new int[]{0, 0, 0, 1000000000, 1000000000, 1000000000, 1000000000}, 1000000000); + } + + //力扣代码 + //leetcode submit region begin(Prohibit modification and deletion) + class Solution { + public List> fourSum(int[] nums, int target) { + List> result = new ArrayList<>(); + if (nums == null || nums.length < 4) { + return result; + } + Arrays.sort(nums); + int length = nums.length; + long sum; + for (int i = 0; i < length - 3; i++) { + if (i > 0 && nums[i] == nums[i - 1]) { + continue; + } + sum = (long)nums[i] + nums[i + 1] + nums[i + 2] + nums[i + 3]; + if (sum > target) { + break; + } + sum = (long)nums[i] + nums[length - 3] + nums[length - 2] + nums[length - 1]; + if (sum < target) { + continue; + } + for (int j = i + 1; j < length - 2; j++) { + if (j > i + 1 && nums[j] == nums[j - 1]) { + continue; + } + sum = (long)nums[i] + nums[j] + nums[j + 1] + nums[j + 2]; + if (sum > target) { + break; + } + sum = (long)nums[i] + nums[j] + nums[length - 2] + nums[length - 1]; + if (sum < target) { + continue; + } + int start = j + 1; + int end = length - 1; + while (start < end) { + sum = (long)nums[i] + nums[j] + nums[start] + nums[end]; + if (sum == target) { + result.add(Arrays.asList(nums[i], nums[j], nums[start], nums[end])); + while (start < end && nums[start] == nums[start + 1]) { + start++; + } + start++; + while (start < end && nums[end] == nums[end - 1]) { + end--; + } + end--; + } else if (sum < target) { + start++; + } else { + end--; + } + } + } + } + return result; + } + } +//leetcode submit region end(Prohibit modification and deletion) + +} \ No newline at end of file diff --git a/src/main/java/leetcode/editor/cn/MergeSortedArray.java b/src/main/java/leetcode/editor/cn/MergeSortedArray.java index b88926e..b77c10a 100644 --- a/src/main/java/leetcode/editor/cn/MergeSortedArray.java +++ b/src/main/java/leetcode/editor/cn/MergeSortedArray.java @@ -51,7 +51,9 @@ public class MergeSortedArray { //leetcode submit region begin(Prohibit modification and deletion) class Solution { public void merge(int[] nums1, int m, int[] nums2, int n) { - if (m + n - m >= 0) System.arraycopy(nums2, 0, nums1, m, m + n - m); + if (m + n - m >= 0) { + System.arraycopy(nums2, 0, nums1, m, m + n - m); + } Arrays.sort(nums1); } } diff --git a/src/main/java/leetcode/editor/cn/doc/content/FourSum.md b/src/main/java/leetcode/editor/cn/doc/content/FourSum.md new file mode 100644 index 0000000..39e6859 --- /dev/null +++ b/src/main/java/leetcode/editor/cn/doc/content/FourSum.md @@ -0,0 +1,36 @@ +

给你一个由 n 个整数组成的数组 nums ,和一个目标值 target 。请你找出并返回满足下述全部条件且不重复的四元组 [nums[a], nums[b], nums[c], nums[d]]

+ + + +

你可以按 任意顺序 返回答案 。

+ +

 

+ +

示例 1:

+ +
+输入:nums = [1,0,-1,0,-2,2], target = 0
+输出:[[-2,-1,1,2],[-2,0,0,2],[-1,0,0,1]]
+
+ +

示例 2:

+ +
+输入:nums = [2,2,2,2,2], target = 8
+输出:[[2,2,2,2]]
+
+ +

 

+ +

提示:

+ + +
Related Topics
  • 数组
  • 双指针
  • 排序

  • 👍 976
  • 👎 0
  • \ No newline at end of file