diff --git a/src/main/java/leetcode/editor/cn/MonotoneIncreasingDigits.java b/src/main/java/leetcode/editor/cn/MonotoneIncreasingDigits.java new file mode 100644 index 0000000..a357dee --- /dev/null +++ b/src/main/java/leetcode/editor/cn/MonotoneIncreasingDigits.java @@ -0,0 +1,59 @@ +//给定一个非负整数 N,找出小于或等于 N 的最大的整数,同时这个整数需要满足其各个位数上的数字是单调递增。 +// +// (当且仅当每个相邻位数上的数字 x 和 y 满足 x <= y 时,我们称这个整数是单调递增的。) +// +// 示例 1: +// +// 输入: N = 10 +//输出: 9 +// +// +// 示例 2: +// +// 输入: N = 1234 +//输出: 1234 +// +// +// 示例 3: +// +// 输入: N = 332 +//输出: 299 +// +// +// 说明: N 是在 [0, 10^9] 范围内的一个整数。 +// Related Topics 贪心 数学 👍 205 👎 0 + +package leetcode.editor.cn; + +//738:单调递增的数字 +class MonotoneIncreasingDigits { + public static void main(String[] args) { + //测试代码 + Solution solution = new MonotoneIncreasingDigits().new Solution(); + } + + //力扣代码 + //leetcode submit region begin(Prohibit modification and deletion) + class Solution { + public int monotoneIncreasingDigits(int n) { + char[] arr = (n + "").toCharArray(); + int max = -1, idx = -1; + for (int i = 0; i < arr.length - 1; i++) { + if (max < arr[i]) { + max = arr[i]; + idx = i; + } + if (arr[i] > arr[i + 1]) { + arr[idx] -= 1; + for (int j = idx + 1; j < arr.length; j++) { + arr[j] = '9'; + } + break; + } + } + return Integer.parseInt(new String(arr)); + } + } +//leetcode submit region end(Prohibit modification and deletion) + +} \ No newline at end of file diff --git a/src/main/java/leetcode/editor/cn/doc/all.json b/src/main/java/leetcode/editor/cn/doc/all.json index 8fa98e8..25fa3a9 100644 --- a/src/main/java/leetcode/editor/cn/doc/all.json +++ b/src/main/java/leetcode/editor/cn/doc/all.json @@ -1 +1 @@ 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给定一个非负整数 N
,找出小于或等于 N
的最大的整数,同时这个整数需要满足其各个位数上的数字是单调递增。
(当且仅当每个相邻位数上的数字 x
和 y
满足 x <= y
时,我们称这个整数是单调递增的。)
示例 1:
+ +输入: N = 10 +输出: 9 ++ +
示例 2:
+ +输入: N = 1234 +输出: 1234 ++ +
示例 3:
+ +输入: N = 332 +输出: 299 ++ +
说明: N
是在 [0, 10^9]
范围内的一个整数。