283:移动零
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src/main/java/leetcode/editor/cn/MoveZeroes.java
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src/main/java/leetcode/editor/cn/MoveZeroes.java
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//给定一个数组 nums,编写一个函数将所有 0 移动到数组的末尾,同时保持非零元素的相对顺序。
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//
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// 示例:
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//
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// 输入: [0,1,0,3,12]
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//输出: [1,3,12,0,0]
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//
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// 说明:
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//
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//
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// 必须在原数组上操作,不能拷贝额外的数组。
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// 尽量减少操作次数。
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//
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// Related Topics 数组 双指针
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// 👍 1110 👎 0
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package leetcode.editor.cn;
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//283:移动零
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class MoveZeroes {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new MoveZeroes().new Solution();
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public void moveZeroes(int[] nums) {
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int low = 0, fast = 1;
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for (; fast < nums.length; fast++) {
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if (nums[low] == 0) {
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if (nums[fast] == 0) continue;
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else {
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int tmp = nums[low];
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nums[low] = nums[fast];
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nums[fast] = tmp;
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low++;
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}
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continue;
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}
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low++;
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}
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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src/main/java/leetcode/editor/cn/MoveZeroes.md
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src/main/java/leetcode/editor/cn/MoveZeroes.md
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<p>给定一个数组 <code>nums</code>,编写一个函数将所有 <code>0</code> 移动到数组的末尾,同时保持非零元素的相对顺序。</p>
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<p><strong>示例:</strong></p>
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<pre><strong>输入:</strong> <code>[0,1,0,3,12]</code>
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<strong>输出:</strong> <code>[1,3,12,0,0]</code></pre>
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<p><strong>说明</strong>:</p>
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<ol>
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<li>必须在原数组上操作,不能拷贝额外的数组。</li>
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<li>尽量减少操作次数。</li>
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</ol>
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<div><div>Related Topics</div><div><li>数组</li><li>双指针</li></div></div>\n<div><li>👍 1110</li><li>👎 0</li></div>
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