401:二进制手表
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src/main/java/leetcode/editor/cn/BinaryWatch.java
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src/main/java/leetcode/editor/cn/BinaryWatch.java
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//二进制手表顶部有 4 个 LED 代表 小时（0-11），底部的 6 个 LED 代表 分钟（0-59）。每个 LED 代表一个 0 或 1，最低位在右侧。
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//
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//
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//
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// 例如，下面的二进制手表读取 "3:25" 。
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//
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//
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//
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//
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// （图源：WikiMedia - Binary clock samui moon.jpg ，许可协议：Attribution-ShareAlike 3.0
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//Unported (CC BY-SA 3.0) ）
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//
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// 给你一个整数 turnedOn ，表示当前亮着的 LED 的数量，返回二进制手表可以表示的所有可能时间。你可以 按任意顺序 返回答案。
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//
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// 小时不会以零开头：
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//
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//
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// 例如，"01:00" 是无效的时间，正确的写法应该是 "1:00" 。
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//
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//
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// 分钟必须由两位数组成，可能会以零开头：
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//
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//
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// 例如，"10:2" 是无效的时间，正确的写法应该是 "10:02" 。
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//
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//
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//
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//
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// 示例 1：
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//
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//
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//输入：turnedOn = 1
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//输出：["0:01","0:02","0:04","0:08","0:16","0:32","1:00","2:00","4:00","8:00"]
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//
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//
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// 示例 2：
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//
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//
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//输入：turnedOn = 9
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//输出：[]
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//
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//
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//
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//
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// 提示：
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//
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//
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// 0 <= turnedOn <= 10
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//
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// Related Topics 位运算 回溯 👍 356 👎 0
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package leetcode.editor.cn;
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import java.util.*;
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//401:二进制手表
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public class BinaryWatch {
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public static void main(String[] args) {
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Solution solution = new BinaryWatch().new Solution();
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// TO TEST
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System.out.println(solution.readBinaryWatch(2));
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}
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public List<String> readBinaryWatch(int turnedOn) {
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if (turnedOn > 8) {
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return new ArrayList<>();
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}
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Map<Integer, Set<Integer>> map1 = getNums(4, turnedOn);
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Map<Integer, Set<Integer>> map2 = getNums(6, turnedOn);
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List<String> list = new ArrayList<>();
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for (int key : map1.keySet()) {
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if (turnedOn - key >= 6) {
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continue;
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}
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for (int hour : map1.get(key)) {
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for (int mini : map2.get(turnedOn - key)) {
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list.add(hour + ":" + String.format("%02d", mini));
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}
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}
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}
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return list;
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}
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private Map<Integer, Set<Integer>> getNums(int line, int turnedOn) {
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Map<Integer, Set<Integer>> map = new HashMap<>(line);
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int[] arrs = new int[line];
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arrs[0] = 1;
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for (int i = 1; i < line; i++) {
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arrs[i] = 2 * arrs[i - 1];
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}
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for (int i = 0; i <= Math.min(line, turnedOn); i++) {
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if (i == 0) {
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map.put(i, new HashSet<>(Collections.singletonList(0)));
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} else {
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Set<Integer> set = map.get(i - 1);
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Set<Integer> cur = new HashSet<>();
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for (int num : set) {
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for (int j = 0; j < line; j++) {
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if ((num & arrs[j]) == 0) {
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if (line == 4 && (num | arrs[j]) < 12) {
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cur.add(num | arrs[j]);
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} else if (line == 6 && (num | arrs[j]) < 60) {
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cur.add(num | arrs[j]);
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}
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}
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}
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}
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map.put(i, cur);
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}
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}
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return map;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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48
src/main/java/leetcode/editor/cn/doc/content/BinaryWatch.md
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src/main/java/leetcode/editor/cn/doc/content/BinaryWatch.md
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<p>二进制手表顶部有 4 个 LED 代表<strong> 小时（0-11）</strong>，底部的 6 个 LED 代表<strong> 分钟（0-59）</strong>。每个 LED 代表一个 0 或 1，最低位在右侧。</p>
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<ul>
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<li>例如，下面的二进制手表读取 <code>"3:25"</code> 。</li>
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</ul>
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<p><img src="https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2021/03/29/binary_clock_samui_moon.jpg" style="height: 300px; width" /></p>
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<p><small><em>（图源：<a href="https://commons.m.wikimedia.org/wiki/File:Binary_clock_samui_moon.jpg">WikiMedia - Binary clock samui moon.jpg</a> ，许可协议：<a href="https://creativecommons.org/licenses/by-sa/3.0/deed.en">Attribution-ShareAlike 3.0 Unported (CC BY-SA 3.0)</a> ）</em></small></p>
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<p>给你一个整数 <code>turnedOn</code> ，表示当前亮着的 LED 的数量，返回二进制手表可以表示的所有可能时间。你可以 <strong>按任意顺序</strong> 返回答案。</p>
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<p>小时不会以零开头：</p>
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<ul>
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<li>例如，<code>"01:00"</code> 是无效的时间，正确的写法应该是 <code>"1:00"</code> 。</li>
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</ul>
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<p>分钟必须由两位数组成，可能会以零开头：</p>
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<ul>
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<li>例如，<code>"10:2"</code> 是无效的时间，正确的写法应该是 <code>"10:02"</code> 。</li>
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</ul>
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<p> </p>
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<p><strong>示例 1：</strong></p>
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<pre>
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<strong>输入：</strong>turnedOn = 1
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<strong>输出：</strong>["0:01","0:02","0:04","0:08","0:16","0:32","1:00","2:00","4:00","8:00"]
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>turnedOn = 9
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<strong>输出：</strong>[]
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>0 <= turnedOn <= 10</code></li>
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</ul>
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<div><div>Related Topics</div><div><li>位运算</li><li>回溯</li></div></div><br><div><li>👍 356</li><li>👎 0</li></div>
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