58:最后一个单词的长度
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src/main/java/leetcode/editor/cn/LengthOfLastWord.java
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src/main/java/leetcode/editor/cn/LengthOfLastWord.java
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//给你一个字符串 s,由若干单词组成,单词前后用一些空格字符隔开。返回字符串中最后一个单词的长度。
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//
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// 单词 是指仅由字母组成、不包含任何空格字符的最大子字符串。
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//
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//
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//
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// 示例 1:
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//
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//
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//输入:s = "Hello World"
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//输出:5
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//
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//
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// 示例 2:
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//
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//
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//输入:s = " fly me to the moon "
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//输出:4
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//
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//
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// 示例 3:
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//
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//
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//输入:s = "luffy is still joyboy"
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//输出:6
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//
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//
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//
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//
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// 提示:
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//
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//
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// 1 <= s.length <= 10⁴
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// s 仅有英文字母和空格 ' ' 组成
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// s 中至少存在一个单词
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//
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// Related Topics 字符串 👍 373 👎 0
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package leetcode.editor.cn;
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//58:最后一个单词的长度
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class LengthOfLastWord {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new LengthOfLastWord().new Solution();
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public int lengthOfLastWord(String s) {
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int size = s.length();
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int count = 0;
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for (int i = size - 1; i >= 0; i--) {
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if (" ".equals("" + s.charAt(i)) && count > 0) {
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break;
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}
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if (!" ".equals("" + s.charAt(i))) {
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count++;
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}
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}
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return count;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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<p>给你一个字符串 <code>s</code>,由若干单词组成,单词前后用一些空格字符隔开。返回字符串中最后一个单词的长度。</p>
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<p><strong>单词</strong> 是指仅由字母组成、不包含任何空格字符的最大子字符串。</p>
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<p> </p>
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<p><strong>示例 1:</strong></p>
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<pre>
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<strong>输入:</strong>s = "Hello World"
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<strong>输出:</strong>5
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</pre>
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<p><strong>示例 2:</strong></p>
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<pre>
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<strong>输入:</strong>s = " fly me to the moon "
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<strong>输出:</strong>4
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</pre>
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<p><strong>示例 3:</strong></p>
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<pre>
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<strong>输入:</strong>s = "luffy is still joyboy"
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<strong>输出:</strong>6
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>1 <= s.length <= 10<sup>4</sup></code></li>
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<li><code>s</code> 仅有英文字母和空格 <code>' '</code> 组成</li>
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<li><code>s</code> 中至少存在一个单词</li>
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</ul>
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<div><div>Related Topics</div><div><li>字符串</li></div></div><br><div><li>👍 373</li><li>👎 0</li></div>
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