面试题 08.08:有重复字符串的排列组合
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//有重复字符串的排列组合。编写一种方法,计算某字符串的所有排列组合。
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//
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// 示例1:
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//
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// 输入:S = "qqe"
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// 输出:["eqq","qeq","qqe"]
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//
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//
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// 示例2:
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//
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// 输入:S = "ab"
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// 输出:["ab", "ba"]
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//
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//
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// 提示:
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//
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//
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// 字符都是英文字母。
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// 字符串长度在[1, 9]之间。
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//
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// Related Topics 回溯算法
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// 👍 37 👎 0
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package leetcode.editor.cn;
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import java.util.*;
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//面试题 08.08:有重复字符串的排列组合
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public class PermutationIiLcci {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new PermutationIiLcci().new Solution();
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solution.permutation("ab");
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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List<String> list;
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public String[] permutation(String S) {
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list = new ArrayList<>();
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char[] str = S.toCharArray();
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Arrays.sort(str);
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boolean[] visited = new boolean[str.length];
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dfs(str, visited, new StringBuilder());
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return list.toArray(new String[0]);
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}
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private void dfs(char[] str, boolean visited[], StringBuilder temp) {
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if (temp.length() == str.length) {
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list.add(temp.toString());
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return;
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}
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for (int i = 0; i < str.length; i++) {
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if (visited[i] || i != 0 && !visited[i - 1] && str[i] == str[i - 1]) {
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continue;
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}
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temp.append(str[i]);
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visited[i] = true;
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dfs(str, visited, temp);
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temp.deleteCharAt(temp.length() - 1);
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visited[i] = false;
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}
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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<p>有重复字符串的排列组合。编写一种方法,计算某字符串的所有排列组合。</p>
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<p><strong>示例1:</strong></p>
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<pre><strong> 输入</strong>:S = "qqe"
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<strong> 输出</strong>:["eqq","qeq","qqe"]
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</pre>
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<p><strong>示例2:</strong></p>
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<pre><strong> 输入</strong>:S = "ab"
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<strong> 输出</strong>:["ab", "ba"]
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</pre>
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<p><strong>提示:</strong></p>
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<ol>
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<li>字符都是英文字母。</li>
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<li>字符串长度在[1, 9]之间。</li>
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</ol>
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<div><div>Related Topics</div><div><li>回溯算法</li></div></div>\n<div><li>👍 37</li><li>👎 0</li></div>
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