784:字母大小写全排列(未完成)
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src/main/java/leetcode/editor/cn/LetterCasePermutation.java
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src/main/java/leetcode/editor/cn/LetterCasePermutation.java
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//给定一个字符串S,通过将字符串S中的每个字母转变大小写,我们可以获得一个新的字符串。返回所有可能得到的字符串集合。
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//
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//
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//
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// 示例:
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//输入:S = "a1b2"
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//输出:["a1b2", "a1B2", "A1b2", "A1B2"]
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//
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//输入:S = "3z4"
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//输出:["3z4", "3Z4"]
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//
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//输入:S = "12345"
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//输出:["12345"]
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//
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//
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//
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//
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// 提示:
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//
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//
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// S 的长度不超过12。
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// S 仅由数字和字母组成。
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//
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// Related Topics 位运算 字符串 回溯
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// 👍 282 👎 0
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package leetcode.editor.cn;
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import java.util.ArrayList;
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import java.util.List;
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//784:字母大小写全排列
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class LetterCasePermutation{
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public static void main(String[] args) {
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//测试代码
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Solution solution = new LetterCasePermutation().new Solution();
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solution.letterCasePermutation("a1b2");
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public List<String> letterCasePermutation(String s) {
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char[] chs = s.toCharArray();
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List<char[]> list = new ArrayList<>();
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list.add(chs);
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for (int i = 0; i < chs.length; i++) {
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if(Character.isDigit(chs[i])){
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continue;
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}
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List<char[]> temp = new ArrayList<>();
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for (char[] chList:list) {
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temp.add(chList);
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if(chList[i]<'a'){
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chList[i] += 32;
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temp.add(chList);
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}else {
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chList[i] -= 32;
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temp.add(chList);
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}
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}
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list = temp;
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}
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List<String> result = new ArrayList<>();
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for (int i = 0; i < list.size(); i++) {
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result.add(new String(list.get(i)));
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}
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return result;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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src/main/java/leetcode/editor/cn/LetterCasePermutation.md
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src/main/java/leetcode/editor/cn/LetterCasePermutation.md
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<p>给定一个字符串<code>S</code>,通过将字符串<code>S</code>中的每个字母转变大小写,我们可以获得一个新的字符串。返回所有可能得到的字符串集合。</p>
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<p> </p>
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<pre><strong>示例:</strong>
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<strong>输入:</strong>S = "a1b2"
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<strong>输出:</strong>["a1b2", "a1B2", "A1b2", "A1B2"]
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<strong>输入:</strong>S = "3z4"
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<strong>输出:</strong>["3z4", "3Z4"]
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<strong>输入:</strong>S = "12345"
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<strong>输出:</strong>["12345"]
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</pre>
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<p> </p>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>S</code> 的长度不超过<code>12</code>。</li>
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<li><code>S</code> 仅由数字和字母组成。</li>
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</ul>
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<div><div>Related Topics</div><div><li>位运算</li><li>字符串</li><li>回溯</li></div></div>\n<div><li>👍 282</li><li>👎 0</li></div>
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