557:反转字符串中的单词 III

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huangge1199 2021-07-09 14:39:45 +08:00
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commit 1e18e2a7aa
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//给定一个字符串你需要反转字符串中每个单词的字符顺序同时仍保留空格和单词的初始顺序
//
//
//
// 示例
//
// 输入"Let's take LeetCode contest"
//输出"s'teL ekat edoCteeL tsetnoc"
//
//
//
//
// 提示
//
//
// 在字符串中每个单词由单个空格分隔并且字符串中不会有任何额外的空格
//
// Related Topics 双指针 字符串
// 👍 300 👎 0
package leetcode.editor.cn;
//557:反转字符串中的单词 III
public class ReverseWordsInAStringIii{
public static void main(String[] args) {
//测试代码
Solution solution = new ReverseWordsInAStringIii().new Solution();
}
//力扣代码
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public String reverseWords(String s) {
StringBuilder str = new StringBuilder();
StringBuilder ss = new StringBuilder();
for (char ch:s.toCharArray()){
if(ch!=' '){
str.append(ch);
}else{
ss.append(str.reverse()).append(" ");
str = new StringBuilder();
}
}
ss.append(str.reverse());
return ss.toString();
}
}
//leetcode submit region end(Prohibit modification and deletion)
}

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<p>给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。</p>
<p>&nbsp;</p>
<p><strong>示例:</strong></p>
<pre><strong>输入:</strong>&quot;Let&#39;s take LeetCode contest&quot;
<strong>输出:</strong>&quot;s&#39;teL ekat edoCteeL tsetnoc&quot;
</pre>
<p>&nbsp;</p>
<p><strong><strong><strong><strong>提示:</strong></strong></strong></strong></p>
<ul>
<li>在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格。</li>
</ul>
<div><div>Related Topics</div><div><li>双指针</li><li>字符串</li></div></div>\n<div><li>👍 300</li><li>👎 0</li></div>