diff --git a/src/main/java/leetcode/editor/cn/MinimumPathSum.java b/src/main/java/leetcode/editor/cn/MinimumPathSum.java
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+//给定一个包含非负整数的 m x n 网格 grid ，请找出一条从左上角到右下角的路径，使得路径上的数字总和为最小。 
+//
+// 说明：每次只能向下或者向右移动一步。 
+//
+// 
+//
+// 示例 1： 
+//
+// 
+//输入：grid = [[1,3,1],[1,5,1],[4,2,1]]
+//输出：7
+//解释：因为路径 1→3→1→1→1 的总和最小。
+// 
+//
+// 示例 2： 
+//
+// 
+//输入：grid = [[1,2,3],[4,5,6]]
+//输出：12
+// 
+//
+// 
+//
+// 提示： 
+//
+// 
+// m == grid.length 
+// n == grid[i].length 
+// 1 <= m, n <= 200 
+// 0 <= grid[i][j] <= 100 
+// 
+// Related Topics 数组 动态规划 矩阵 
+// 👍 955 👎 0
+
+package leetcode.editor.cn;
+
+import com.code.leet.entiy.TwoArray;
+
+//64:最小路径和
+class MinimumPathSum {
+    public static void main(String[] args) {
+        //测试代码
+        Solution solution = new MinimumPathSum().new Solution();
+        TwoArray twoArray = new TwoArray("[[1,3,1],[1,5,1],[4,2,1]]", true);
+        System.out.println(solution.minPathSum(twoArray.getArr()));
+    }
+
+    //力扣代码
+    //leetcode submit region begin(Prohibit modification and deletion)
+    class Solution {
+        public int minPathSum(int[][] grid) {
+            int[][] dp = new int[grid.length][grid[0].length];
+            for (int i = 0; i < grid.length; i++) {
+                for (int j = 0; j < grid[0].length; j++) {
+                    if (i > 0 && j > 0) {
+                        dp[i][j] = grid[i][j] + Math.min(dp[i - 1][j], dp[i][j - 1]);
+                    } else if (i > 0) {
+                        dp[i][j] = grid[i][j] + dp[i - 1][j];
+                    } else if (j > 0) {
+                        dp[i][j] = grid[i][j] + dp[i][j - 1];
+                    } else {
+                        dp[i][j] = grid[i][j];
+                    }
+                }
+            }
+            return dp[grid.length - 1][grid[0].length - 1];
+        }
+    }
+//leetcode submit region end(Prohibit modification and deletion)
+
+}
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diff --git a/src/main/java/leetcode/editor/cn/MinimumPathSum.md b/src/main/java/leetcode/editor/cn/MinimumPathSum.md
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+<p>给定一个包含非负整数的 <code><em>m</em> x <em>n</em></code> 网格 <code>grid</code> ，请找出一条从左上角到右下角的路径，使得路径上的数字总和为最小。</p>
+
+<p><strong>说明：</strong>每次只能向下或者向右移动一步。</p>
+
+<p> </p>
+
+<p><strong>示例 1：</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2020/11/05/minpath.jpg" style="width: 242px; height: 242px;" />
+<pre>
+<strong>输入：</strong>grid = [[1,3,1],[1,5,1],[4,2,1]]
+<strong>输出：</strong>7
+<strong>解释：</strong>因为路径 1→3→1→1→1 的总和最小。
+</pre>
+
+<p><strong>示例 2：</strong></p>
+
+<pre>
+<strong>输入：</strong>grid = [[1,2,3],[4,5,6]]
+<strong>输出：</strong>12
+</pre>
+
+<p> </p>
+
+<p><strong>提示：</strong></p>
+
+<ul>
+	<li><code>m == grid.length</code></li>
+	<li><code>n == grid[i].length</code></li>
+	<li><code>1 <= m, n <= 200</code></li>
+	<li><code>0 <= grid[i][j] <= 100</code></li>
+</ul>
+<div><div>Related Topics</div><div><li>数组</li><li>动态规划</li><li>矩阵</li></div></div>\n<div><li>👍 955</li><li>👎 0</li></div>
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