leet-code/src/main/java/leetcode/editor/cn/NAryTreeLevelOrderTraversal.java

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2021-08-12 11:26:22 +08:00
//给定一个 N 叉树,返回其节点值的层序遍历。(即从左到右,逐层遍历)。
//
// 树的序列化输入是用层序遍历,每组子节点都由 null 值分隔(参见示例)。
//
//
//
// 示例 1
//
//
//
//
//输入root = [1,null,3,2,4,null,5,6]
//输出:[[1],[3,2,4],[5,6]]
//
//
// 示例 2
//
//
//
//
//输入root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,
//null,13,null,null,14]
//输出:[[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]
//
//
//
//
// 提示:
//
//
// 树的高度不会超过 1000
// 树的节点总数在 [0, 10^4] 之间
//
// Related Topics 树 广度优先搜索
// 👍 170 👎 0
package leetcode.editor.cn;
import com.code.leet.entiy.Node;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
//429:N 叉树的层序遍历
class NAryTreeLevelOrderTraversal {
public static void main(String[] args) {
//测试代码
Solution solution = new NAryTreeLevelOrderTraversal().new Solution();
}
//力扣代码
//leetcode submit region begin(Prohibit modification and deletion)
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> children;
public Node() {}
public Node(int _val) {
val = _val;
}
public Node(int _val, List<Node> _children) {
val = _val;
children = _children;
}
};
*/
class Solution {
public List<List<Integer>> levelOrder(Node root) {
if (root == null) {
return new ArrayList<>();
}
Queue<Node> queue = new LinkedList<>();
queue.add(root);
List<List<Integer>> result = new ArrayList<>();
while (!queue.isEmpty()) {
int size = queue.size();
List<Integer> list = new ArrayList<>();
for (int i = 0; i < size; i++) {
Node node = queue.poll();
list.add(node.val);
List<Node> nodeList = node.children;
for (Node temp : nodeList) {
queue.add(temp);
}
}
result.add(list);
}
return result;
}
}
//leetcode submit region end(Prohibit modification and deletion)
}