53 lines
1.3 KiB
Markdown
53 lines
1.3 KiB
Markdown
|
<p>给定一个整数数组 <code>nums</code> ，找到一个具有最大和的连续子数组（子数组最少包含一个元素），返回其最大和。</p>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>示例 1：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>nums = [-2,1,-3,4,-1,2,1,-5,4]
|
|||
|
|
<strong>输出：</strong>6
|
|||
|
|
<strong>解释：</strong>连续子数组 [4,-1,2,1] 的和最大，为 6 。
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 2：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>nums = [1]
|
|||
|
|
<strong>输出：</strong>1
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 3：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>nums = [0]
|
|||
|
|
<strong>输出：</strong>0
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 4：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>nums = [-1]
|
|||
|
|
<strong>输出：</strong>-1
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 5：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>nums = [-100000]
|
|||
|
|
<strong>输出：</strong>-100000
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>提示：</strong></p>
|
|||
|
|
|
|||
|
|
<ul>
|
|||
|
|
<li><code>1 <= nums.length <= 3 * 10<sup>4</sup></code></li>
|
|||
|
|
<li><code>-10<sup>5</sup> <= nums[i] <= 10<sup>5</sup></code></li>
|
|||
|
|
</ul>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>进阶：</strong>如果你已经实现复杂度为 <code>O(n)</code> 的解法，尝试使用更为精妙的 <strong>分治法</strong> 求解。</p>
|
|||
|
|
<div><div>Related Topics</div><div><li>数组</li><li>分治</li><li>动态规划</li></div></div>\n<div><li>👍 3368</li><li>👎 0</li></div>
|