72 lines
2.0 KiB
Java
72 lines
2.0 KiB
Java
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//给定 n 个非负整数，用来表示柱状图中各个柱子的高度。每个柱子彼此相邻，且宽度为 1 。
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//
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// 求在该柱状图中，能够勾勒出来的矩形的最大面积。
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//
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//
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// 以上是柱状图的示例，其中每个柱子的宽度为 1，给定的高度为 [2,1,5,6,2,3]。
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//
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//
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//
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//
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//
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// 图中阴影部分为所能勾勒出的最大矩形面积，其面积为 10 个单位。
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//
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//
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//
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// 示例:
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//
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// 输入: [2,1,5,6,2,3]
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//输出: 10
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// Related Topics 栈 数组
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// 👍 1383 👎 0
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package leetcode.editor.cn;
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import java.util.Stack;
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//84:柱状图中最大的矩形
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public class LargestRectangleInHistogram {
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public static void main(String[] args) {
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//测试代码
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Solution solution = new LargestRectangleInHistogram().new Solution();
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}
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//力扣代码
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//leetcode submit region begin(Prohibit modification and deletion)
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class Solution {
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public int largestRectangleArea(int[] heights) {
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int length = heights.length;
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int[] left = new int[length];
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int[] right = new int[length];
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Stack<Integer> stack = new Stack<Integer>();
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for (int i = 0; i < length; ++i) {
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while (!stack.isEmpty() && heights[stack.peek()] >= heights[i]) {
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stack.pop();
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}
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left[i] = (stack.isEmpty() ? -1 : stack.peek());
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stack.push(i);
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}
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stack.clear();
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for (int i = length - 1; i >= 0; --i) {
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while (!stack.isEmpty() && heights[stack.peek()] >= heights[i]) {
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stack.pop();
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}
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right[i] = (stack.isEmpty() ? length : stack.peek());
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stack.push(i);
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}
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int ans = 0;
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for (int i = 0; i < length; ++i) {
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ans = Math.max(ans, (right[i] - left[i] - 1) * heights[i]);
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}
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return ans;
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}
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}
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//leetcode submit region end(Prohibit modification and deletion)
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}
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