2021-08-04 19:38:49 +08:00
|
|
|
//给定一个包含非负整数的数组,你的任务是统计其中可以组成三角形三条边的三元组个数。
|
|
|
|
//
|
|
|
|
// 示例 1:
|
|
|
|
//
|
|
|
|
//
|
|
|
|
//输入: [2,2,3,4]
|
|
|
|
//输出: 3
|
|
|
|
//解释:
|
|
|
|
//有效的组合是:
|
|
|
|
//2,3,4 (使用第一个 2)
|
|
|
|
//2,3,4 (使用第二个 2)
|
|
|
|
//2,2,3
|
|
|
|
//
|
|
|
|
//
|
|
|
|
// 注意:
|
|
|
|
//
|
|
|
|
//
|
|
|
|
// 数组长度不超过1000。
|
|
|
|
// 数组里整数的范围为 [0, 1000]。
|
|
|
|
//
|
|
|
|
// Related Topics 贪心 数组 双指针 二分查找 排序
|
|
|
|
// 👍 252 👎 0
|
|
|
|
|
|
|
|
package leetcode.editor.cn;
|
|
|
|
|
|
|
|
import java.util.Arrays;
|
|
|
|
|
|
|
|
//611:有效三角形的个数
|
|
|
|
class ValidTriangleNumber {
|
|
|
|
public static void main(String[] args) {
|
|
|
|
//测试代码
|
|
|
|
Solution solution = new ValidTriangleNumber().new Solution();
|
|
|
|
}
|
|
|
|
|
|
|
|
//力扣代码
|
|
|
|
//leetcode submit region begin(Prohibit modification and deletion)
|
|
|
|
class Solution {
|
|
|
|
public int triangleNumber(int[] nums) {
|
|
|
|
Arrays.sort(nums);
|
|
|
|
int count = 0;
|
|
|
|
for (int i = 0; i < nums.length; i++) {
|
|
|
|
for (int j = i - 1; j >= 0; j--) {
|
2021-08-04 19:44:15 +08:00
|
|
|
// int k = 0;
|
|
|
|
// while (k < j && nums[j] + nums[k] <= nums[i]) {
|
|
|
|
// k++;
|
|
|
|
// }
|
|
|
|
// count += j - k;
|
|
|
|
int start = 0, end = j - 1;
|
|
|
|
while (start < end) {
|
|
|
|
int mid = start + end >> 1;
|
|
|
|
if (nums[mid] + nums[j] > nums[i]) {
|
|
|
|
end = mid;
|
|
|
|
} else {
|
|
|
|
start = mid + 1;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
if (start == end && nums[end] + nums[j] > nums[i]) {
|
|
|
|
count += j - end;
|
2021-08-04 19:38:49 +08:00
|
|
|
}
|
|
|
|
}
|
|
|
|
}
|
|
|
|
return count;
|
|
|
|
}
|
|
|
|
}
|
|
|
|
//leetcode submit region end(Prohibit modification and deletion)
|
|
|
|
|
|
|
|
}
|