leet-code/src/main/java/leetcode/editor/cn/SearchA2dMatrix.java

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2021-08-12 13:34:48 +08:00
//编写一个高效的算法来判断 m x n 矩阵中,是否存在一个目标值。该矩阵具有如下特性:
//
//
// 每行中的整数从左到右按升序排列。
// 每行的第一个整数大于前一行的最后一个整数。
//
//
//
//
// 示例 1
//
//
//输入matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3
//输出true
//
//
// 示例 2
//
//
//输入matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13
//输出false
//
//
//
//
// 提示:
//
//
// m == matrix.length
// n == matrix[i].length
// 1 <= m, n <= 100
// -104 <= matrix[i][j], target <= 104
//
// Related Topics 数组 二分查找 矩阵
// 👍 478 👎 0
package leetcode.editor.cn;
import com.code.leet.entiy.TwoArray;
//74:搜索二维矩阵
class SearchA2dMatrix {
public static void main(String[] args) {
//测试代码
Solution solution = new SearchA2dMatrix().new Solution();
//true
// TwoArray twoArray = new TwoArray("[[1,3,5,7],[10,11,16,20],[23,30,34,60]]",true);
// System.out.println(solution.searchMatrix(twoArray.getArr(), 3));
//true
TwoArray twoArray = new TwoArray("[[1,3]]", true);
System.out.println(solution.searchMatrix(twoArray.getArr(), 3));
}
//力扣代码
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public boolean searchMatrix(int[][] matrix, int target) {
if (target < matrix[0][0] || target > matrix[matrix.length - 1][matrix[0].length - 1]) {
return false;
}
int start = 0;
int end = matrix.length - 1;
while (start < end - 1) {
int mid = (start + end) / 2;
if (matrix[mid][0] == target) {
return true;
}
if (matrix[mid][0] > target) {
end = mid - 1;
} else {
start = mid;
}
}
if (matrix[end][0] == target) {
return true;
}
int xIndex = matrix[end][0] > target ? start : end;
start = 0;
end = matrix[0].length - 1;
while (start < end) {
int mid = (start + end) / 2;
if (matrix[xIndex][mid] == target) {
return true;
}
if (matrix[xIndex][mid] < target) {
start = mid + 1;
} else {
end = mid;
}
}
return matrix[xIndex][start] == target;
}
}
//leetcode submit region end(Prohibit modification and deletion)
}